Quadratic function and quadratic equation of one variable! 1. The number of intersections of quadratic function y = 2 (x + 2) (x-1) and x-axis is -- and the coordinates of the intersections are—— 2. When m -- the parabola y = x ^ - x + m has an intersection with the X axis 3. If the quadratic function y = 3x ^ + 3x-6 has an intersection with the x-axis, and the coordinates of the intersection are -, then we can see that the quadratic equation 3x ^ + 3x-6 = 0 has a solution, that is, the solution is - 4. Given quadratic function y = 2x ^ - (M + 1) x + (m-1) (1) It is proved that no matter what the value of M is, the image of function y always has an intersection with X axis, and it is pointed out that when the value of M is, there is only one intersection with X axis 5. It is known that the parabola y = ax ^ + 4x + 3 has only one intersection point a with the X axis, and the intersection point with the Y axis is B. try to find the coordinates of a and B and the length of the line ab 6. Given that the image of quadratic function y = x ^ - 2x-3 intersects with X axis at points a and B, there is a point C on the parabola above X axis, and the area of triangle ABC is 10, the coordinate of point C is obtained One two three questions only need to give the result directly. Four five six three questions need the concrete process
Two, (1,0), (- 2,0) m ≤ 1 / 4 (1,0), (- 2,0); X1 = 1. X2 = - 2Y = 2x ^ - (M + 1) x + (m-1) & nbsp; △ = (M + 1) & # 178; - 4 × 2 × (m-1) & nbsp; & nbsp; = M & # 178; - 6m + 9 = (M-3) & # 178; ≥ 0, so there is always an intersection point; when m = 3, there is only one intersection point
Y = 4x + 1, y = - 4x + 1, y = 4x + 1 the list of drawing function image
Y = 4x + 1 y = - 4x + 1 y = 4x + 1 how to calculate the number in the list when drawing function image
You can find any number of generations, such as x = 0, y = 1
Y = - 4x draw the function image
When x = 0, y = 0
When x = 1, y = - 4
Find the line connecting the two points
This can be recommended
If the image of quadratic function y = AX2 + BX + C (a = / 0) is as shown in the figure, (the opening is upward, and the vertex is in the fourth quadrant), then the line y = bx-c does not pass through the fourth quadrant
Because the opening is up
So a > 0
Because the vertex is in the fourth quadrant
So the axis of symmetry x = - B / 2A > 0
So B0, y = bx-c does not pass through the first quadrant
If the intersection of the image and the y-axis is on the negative half axis of Y, then C
In order to make the image of function y = (2m-3) x-3m + 1 pass through two three four quadrants, the values of M and n should be
K=2m-3
Mr. Wang asked the students to consider a linear function. Please give a property to this function
A: the function image passes through the second quadrant and does not pass through the third quadrant
B: when x > 0, y < 0
C: y decreases with the increase of X
D: when x = - 2, y = 3
Please write out the functional relationship suitable for the above four conditions
Let the first-order function y = ax + B
When x > 0, y < 0, it means that the function image passes through the fourth quadrant
So the image is in quadrant two or four, so B = 0
When x = - 2, y = 3
3 = - 2A, a = - 3 / 2
Function relation: y = - 3 / 2x
Mr. Zhang gave a function y = f (x), and four students pointed out a property of this function
The teacher gave a function graph y = f (x), and four students pointed out the properties of this function
A: for the graph where x belongs to R function, it is symmetric with respect to the straight line x = 1
B: on (- infinity, 0), the function decreases
C: increasing function on (0, + infinity]
D: F (0) is not the minimum of a function
Can the answer be y = - x ^ 2-1?
y=-x^2-1
A: for the graph where x belongs to R function, it is symmetric with respect to the straight line x = 1
B: on (- infinity, 0), the function decreases
C: increasing function on (0, + infinity]
It doesn't match
Only D: F (0) is not the minimum value of a function. F (0) = - 1, where y is smaller than - 1, there is an infinite number
So can't the answer be y = - x ^ 2-1?
I feel that there is something wrong with the topic. It is impossible to meet all four conditions
The teacher gives a function y = f (x), and four students a, B, C and D point out a property of the function: A: Yes
The teacher gives a function y = f (x), and four students a, B, C and D point out a property of this function: A: for X ∈ R, f (1 + x) = f (1-x); B: on (- ∞, 0), the function increases; C: on (0, + ∞), the function increases; D: F (0) is not the minimum value of the function
If three of them are right, write a function like this
A: it shows that the function is symmetric with respect to x = 1
B: the function increases in the negative half of X
C: the function increases in the positive half of X
D: F (0) is not the minimum
Obviously, if a is right, because of the symmetry, then B and C must be wrong. But also because the symmetry axis is x = 1, it is impossible to increase or decrease in a certain x half region (only x = 1 as the boundary)
Therefore, only a is incorrect. The other three are correct. For example, y = x ^ 3
Write a function satisfying the following conditions: (1) its image is a straight line passing through the origin; (2) y increases with the increase of X
The results are as follows: 1
A positive proportional function
The results are as follows (2)
K>0
example:
y=5x
y=2.5x
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What are the properties of two function images about the origin symmetry
What is the necessary and sufficient condition? How to deduce one from another?
Y = f (x) and y = - f (x) are symmetric about the X axis
Y = f (x) y = (- x) about Y-axis symmetry
Y = - f (- x) and y = f (x) are symmetric about the origin