If the solution of the system of equations 2x + 5Y = 6 ax + 4Y = 6 is a solution of X + y = 12, find a

If the solution of the system of equations 2x + 5Y = 6 ax + 4Y = 6 is a solution of X + y = 12, find a

a=5/3,x=18,y=-6

It is known that the f (x) image and the function H (x) = 1 / 3x Λ 2 + X Λ 2 + 2 are symmetric with respect to a (0,1) point

Given that the image of function f (x) and the image of function H (x) = (1 / 3) x & sup3; + X & sup2; + 2 are symmetric about a (0,1) point, (1) find the analytic expression of F (x) (2) if G (x) = f (x) + ax, and G (x) is an increasing function on R, find the value range of real number a (1) (x, f (x)) and (T, H (T)) symmetric about (0,1) - > x + T = 0 ---

Given that the function f (x) = ax + B / x + C (a, B, C are constants) is odd and satisfies f (1) = 5 / 2, f (2) = 17 / 4, the values of a, B, C are obtained

a=2 b=1/2 c=0
Analysis: because the function f (x) = ax + B / x + C (a, B, C are constants) is an odd function
So C = 0 (the constant term of odd function is 0)
And because f (1) = 5 / 2, f (2) = 17 / 4
So a + B = 5 / 2
2a+b/2=17/4
A = 2
b=1/2
c=0、

Given that the function f (x) = ax + B / x + C (a, B, C are constants) is odd and satisfies f (1) = 5 / 2, f (2) = 17 / 4, find the value of a, B, C
Given that the function f (x) = ax + B / x + C (a, B, C are constants) is odd and satisfies f (1) = 5 / 2, f (2) = 17 / 4, find the value of a, B, C. try to judge the monotonicity of function f (x) in the interval (0,1 / 2) and explain

From F (- x) = - f (x), C = 0
By taking f (1) = 5 / 2, f (2) = 17 / 4 into the original formula, we get a = 2, B = 1 / 2
f(x)=2x+1/(2x)
Take X1 and X2 to satisfy 0