Who knows AAA + BBB + CCC = fghi AAA + DDD + EEE = fghi to find abcdefghi

Who knows AAA + BBB + CCC = fghi AAA + DDD + EEE = fghi to find abcdefghi

Fghi must be a multiple of 111, 111 * 9

It is known that ABC is a trigonometric trilateral length, reduced ia-b + ci-ia-b-ci

The difference between the two sides must be less than the third side, so the absolute value of A-B + C is still positive, that is, A-B + C
So a-b-c is negative, so the absolute value is - A + B + C
After integration, it was 2C

Let a, B, C and d be the three sides of a triangle, then the following algebraic formula is simplified: Ia + B + CI + ia-b-ci + ib-c-ai = ()

Let a, B, C be the three sides of the triangle, so a + B + C > 0 a-b-c

⊙ o is the inscribed circle of △ ABC, angle c = 90 °, the extension line of Bo intersects AC at point E, BC = 4, CE = 1, and the radius of ⊙ o is calculated

Make ed perpendicular to AB and D
Then de = CE = 1 BD = BC = 4
From the angle bisector theorem, BC: ab = Ce: AE
Let AE = C = x, then ad = root (x-1)
4: 4 + radical (x-1) = 1: X
The solution is x = 1 / 15 (rounding off) x = 17
Then the length of the three sides of the right triangle is 4, 18 and 12 times the root 2
(4 + 18 + 12 times radical 2) * r = 4 * 18
R = do it yourself