The area formula of triangle formed by linear function y = KX + B and coordinate axis I want to summarize the reasoning process and formula

The area formula of triangle formed by linear function y = KX + B and coordinate axis I want to summarize the reasoning process and formula

The coordinate of the intersection point with the X axis is (- B / K, 0)
The coordinate of the intersection point with y axis is (0, b)
Therefore, the area = | - B / K ×| - B | / 2 = B & # / 2 ||

In the circuit, R1 = 2 ohm, R2 = 3 ohm. When S1 is closed and s2s3 is open, the current indication is 0.6A. When S1, S2 and S3 are closed, the current indication is 0.6A,
If the current indication is 1.5A and the bulb lights normally, the power supply voltage and the rated power of the bulb are calculated with the power supply voltage unchanged

When the switch S1 is closed and the switch s2s3 is open, r1r2 is connected in series, and the power supply voltage U = IR = I (R1 + R2) = 0.6A * (2 Ω + 3 Ω) = 3V. When the switches S1, S2 and S3 are closed, R1 is short circuited, the bulb and R2 are connected in parallel, and the total current is I = 1.5A. The normal lighting of the bulb indicates that the rated voltage is equal to the power supply voltage U = 3V. I2 = u / r2 = 3V / 3 Ω = 1ail = i-i2

As shown in the figure, the power supply voltage remains unchanged. Only close the switch S1, the bulb l lights up normally, and then close the switch S2, then ()
A. The current indicates that the number increases and the lamp turns on B. the current indicates that the number decreases and the lamp turns dark C. the rated power of the small bulb increases D. the total power in the circuit increases

When only S1 is closed, only L is connected to the circuit. When S2 is closed, R and L are connected in parallel, and the total resistance decreases, then the main circuit increases and the current indication number increases. After parallel connection, the power supply voltage remains unchanged, that is, the voltage on L remains unchanged, and the power and brightness can be obtained by P = u2r, so a, B and C are all wrong. According to the power formula P = UI, the total voltage remains unchanged, but the total current becomes larger, so the total power becomes smaller So D is correct. So D is chosen

As shown in the figure, the power supply voltage remains unchanged. Close the switches S1 and S2, the voltage indication is 6V, and the current indication is 0.6A. After S2 is disconnected, the voltage indication becomes 2V, and the resistance values of R1 and R2 are calculated

According to the circuit diagram, close the switches S1 and S2, the voltmeter measures the voltage of the power supply, and the ammeter measures the current in the circuit. The resistance value of R1 can be obtained from I = ur: R1 = UI = 6v0.6a = 10 Ω; after disconnecting S2, R1 and R2 are connected in series, and the voltmeter measures the voltage at both ends of R1, ∵ the total voltage in the series circuit is equal to the sum of the partial voltages, ∵ R2 two

As shown in Figure 1, s1.s2 and S3 are the area of a semicircle with the diameter of A.B. and C. you can find the percentage of s1.s2 and S3
(1) As shown in Figure 1, s1.s2 and S3 are the area of a semicircle with the diameter of A.B. and C. can you find out the relationship between s1.s2 and S3? Please explain the reason
(2) As shown in Figure 2, if the right side length of a right triangle is 6cm and 8cm respectively, can you use the conclusion in (1) to calculate the area of the shadow? What else can you draw?

s1^2+s2^2=s3^2

In the known triangle ABC, ∠ ACB = 90 °, take each side of the triangle ABC as an edge and make three squares outside the triangle. S1, S2 and S3 represent the three positive angles respectively
If S1 = 6 and S3 = 25, then S2 =?

Let AC = a, BC = B, ab = C, let AC = a, BC = B, ab = C, then \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\-6 = 19. Satisfied

If the lengths of the three sides of the right triangle ABC are taken as squares, the relationship between their areas S1, S2 and S3 is as follows

S1+S2=S3

A formula for calculating acceleration by successive difference method in physics of grade one of senior high school (with explanation)
I know seven points first, then S4-S1 s5-s2 s6-s3
I can't figure out why a = (S4 + S5 + S6) - (S1 + S2 + S3) / 9at ^ 2 is finally divided by A

You don't have to divide by a!

The first three second displacement is S1, and the last three second displacement is S2 if S1-S2 = 6m
If S1-S2 = 6m, S1 / S2 = 3 / 7, calculate the length of the inclined plane

Since the object at the top of the inclined plane by static uniform acceleration sliding speed should be greater and greater, at the same time, the relative displacement of equal time should be greater and greater, but S1-S2 0, so I think there is a problem with the title
If it's slowing down, it's possible

It is known that s2-s1 = 1.2m, S1: S2 = 3:7, and the total length of the inclined plane

If the total time is t and the acceleration is a, then:
S1＝1/2 a 3^2=9/2 a
S2=1/2 a t^2 - 1/2 a (t-3)^2=3/2 a (2t-3)
S2-S1=3/2 a (2t-3) - 9/2 a =1.2
S1:S2=9/2 a : 3/2 a (2t-3) =3:7
T = 5S, a = 0.2m/s ^ 2
The total length of slope is s = 1 / 2 a T ^ 2 = 1 / 2 * 0.2 * 5 ^ 2 = 2.5m