Why is the average acceleration equal to the instantaneous acceleration in the uniform linear motion

Why is the average acceleration equal to the instantaneous acceleration in the uniform linear motion

The average acceleration only reflects the change of particle velocity in a period of time. The shorter the time is, the closer it is to the actual acceleration of the position. When the time is taken as the minimum, the average acceleration is the instantaneous acceleration

Is the average acceleration the same as the instantaneous acceleration in the uniform linear motion?

The same
The concept of uniform linear motion is the linear motion with constant acceleration
The acceleration is the same, the average is not the same

Whether the average acceleration is the same as the instantaneous acceleration in the uniform linear motion
I'm in a hurry

It's the same, but few people use the word instant acceleration to ask: I'm wrong in my book. Answer: what do you say in your book? Ask: no matter, ask the teacher tomorrow

8 / 35 = 1 / A + 1 / B + 1 / C + 1 / D, where ABCD is different natural number, find the value of ABCD

We can expand 8 / 35 to 24 / 105, and calculate the factors of 105: 1, 3, 5, 7, 15 The answers are 105, 35, 21, 7

In the following four equations, ABCD represents a number, a = B + 3; C = a + A; d = a + C + 7; d = B + 40

C=A+A=B+3+B+3
D=B+40=A+C+7
So B + 40 = a + C + 7 = B + 3 + B + 3 + B + 3 + 7
B+40=3B+16
The solution is b = 12
So a = 15, C = 30, d = 52

ABCD words (B and D are numbers)

Three times and four times, three times and four times, three times and four times, three times and four times, three times and four times, three times and four times, three times and four times, three times and four times, one after another, one time and two times, one time and two times, one time and two times, one time and two times, one time and two times, one time and two times, one time and two times, one time and two times, one time and two times, one time and two times, one time and two times, one time and two times

Sort ABCD a * 5 / 6 = b * 2 / 3 = C * 5 / 4 = D * 8 / 3

b>a>c>d
A * 5 / 6 = b * 2 / 3 = C * 5 / 4 = D * 8 / 3
Multiply by 12
10a=8b=15c=32d
The smaller the coefficient is, the larger the value is
b>a>c>d

It is known that a multiplied by 6 / 5 = 3 / 4 multiplied by B = C divided by 3 / 20 = D divided by 3 / 2

A times 6 / 5 = B times 3 / 4 = C times 20 / 3 = D times 2 / 3, then divide them all, C

4.6 times 8 plus 4 and 5 / 3 times 2

This classmate, are you writing wrong? Is 4.6 * 8 + 4 and 3 / 5 * 2 4 and 3 / 5!
4.6 = 4 and 3 / 5, got it!
Then you can easily calculate 4.6 * (8 + 2) = 4.6 * 10 = 46

(5 / 8 + 5 / 6) multiply by 4 / 25

(5 / 8 + 5 / 6) x 25 / 4
=(5/8)x(4/25)+(5/6)x(4/25)
=1/10+2/15
=3/30+4/30
=7/30
=7 out of 30