Cosa + 2sina = - finding Tana under five roots It's five under the negative root

Cosa + 2sina = - finding Tana under five roots It's five under the negative root

Cosa + 2sina = - radical five
cosa^2+sina^2=1
Two unknowns and two equations can be solved simultaneously

LG and LN, what is the relationship between these two and log? Why is the LN base of LG gone?

The base number of LG is 10, the base number of LN is e, e is a Changshu! These are the derivative forms of log

If logx means log10x (10 is the base), and log (5x ^ 2) = a, then log (4 / x ^ 2)=
If logx represents the base of log 10x and log (5x ^ 2) = a, then log (4 / x ^ 4)=

log(5x^2)=a
log5+logx^2=a
logx^2=a-log5
log(4/x^2)
=log4-logx^2
=log4-a+log4
=lig20-a

It is known that LG 2 = A and LG 3 = B. try to use a and B to represent log 12 base 5 logarithm

log 12( 5)
=lg5/lg12
=(1-lg2)/lg(2^2*3)
=(1-lg2)/(lg2^2+lg3)
=(1-lg2)/(2lg2+lg3)
=(1-a)/(2a+b)

The relationship between logx and log (- x) images
It is helpful for the responder to give an accurate answer

On Y-axis symmetry

Find the value of X. & 10102; Log & 8323; X = - 3 / 4 & 10103; logx bottom 3 = - 3 / 5

1. I didn't understand the question··

Let f (x) be an odd function defined on R. if f (x) = log (3) (1 + x) when x ≥ 0, then f (- 2) =?

-1

Let f (x) be an odd function over R. if f (x) = log3 ^ 1 + X when x is greater than or equal to 0, then f (- 2)=
I want a specific process, that is why. Very much need not go away!

F (x) is an odd function over R, f (- x) = - f (x)
f(-2)=-f(2)=-log3(1+x)=-log3(3)=-1

If x ≥ 0, f (x) = log3 (1 + x), then f (- 2)=______ ．

∵ when x ≥ 0, f (x) = log3 (1 + x), ∵ f (2) = log3 (1 + 2) = 1; ∵ f (x) is an odd function defined on real number r, ∵ f (- 2) = - f (2) = - 1

F (x) is an odd function defined on R, satisfying that f (x + 2) = f (x). When x belongs to (0,1), f (x) = 2 ^ X - 2, then what is the value of 6 at the end of 1 / 2 of log?
Want detailed process. Thank you!

log6=-log6∈（-3,-2）,
∴f(log6)
=f(2+log6)
=-f[-2-log6]
=-2^(-4+log6)
=-3/8.