If f (- 1) = 0, then the inequality f (x)

If f (- 1) = 0, then the inequality f (x)

f(-1)=-f(1)=0
Monotone increasing of odd function f (x) on (- ∞, 0)
The odd function f (x) increases monotonically on (0, + ∞)
Inequality f (x)

If f (x) is an odd function, monotonically increasing on (0, positive infinity) and f (1) = 0, then the inequality x multiplies f (x)

Let f (x) be an odd function, monotonically increasing on (0, positive infinity), and f (1) = 0
have to
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If the odd function f (x) satisfies: 1, f (x) monotonically increases in (0, + ∞); 2, f (1) = 0, then the solution set of inequality (x-1) f (x) > 0 is?

0