Given that the image of a function y = (1-2a) x + A-1 does not pass through the first quadrant, then the value range of a is?

Given that the image of a function y = (1-2a) x + A-1 does not pass through the first quadrant, then the value range of a is?

It is known that the image of a function y = (1-2a) x + A-1 does not pass through the first quadrant,
1-2A

If △ ABC ～ △ DEF is known, and the similarity ratio is k, then the image with a straight line y = KX + K must pass through quadrant a-223 b-2334 c-134 d-1244

Because △ ABC ～ △ def, and the similarity ratio is k, the similarity ratio should be positive, that is, k > 0, the slope k > 0, and the intercept on the Y axis is k, so k > 0. Therefore, the image with a straight line y = KX + K must pass through the (a-23) quadrant

If the image of function y = KX + B passes through the first, second and third quadrants, then () A.B > 0, B.B < 0, C.B = 0, d.bb < or equal to 0

The answer is a. if the image passes through 1 / 3 quadrants, it means k > 0. If it passes through 2 quadrants, b > 0

Given that the function of degree y = KX + B passes through the first, second and fourth quadrants, then K_ 0,b_ 0 (fill in) for detailed explanation

After two or four quadrants, K is less than 0
Through a quadrant, move up through a straight line, b > 0