If 45 ＜ x ＜ 90, then the maximum value of function y = tan2x (TaNx) to the third power is?

If 45 ＜ x ＜ 90, then the maximum value of function y = tan2x (TaNx) to the third power is?

In order to make t = t = Tan \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\it's not easy

(1) The range of function y = 5sinx + cosx is (2) if (π / 4)

(1) Y = radical 6 * (5 / radical 6 * SiNx + 1 / radical 6 * cosx)
=Radical 6 * sin (x + T) {cost = 5 / radical 6, Sint = 1 / radical 6}
So - radical 6 y radical 6
（2）tan2x=2tanx/1-(tanx)^2
y=2tanx^4/1-tanx^2=2/(1/tanx^4-1/tanx^2)
Because TaNx > 1, 0

If TaNx = 1,3sinb = sin (2x + b), then the value of tanb

TaNx = 1, let x = 45 degrees. So 2x = 90 degrees. So 3sinb = sin (90 + b) = CoSb. So tanb = SINB / CoSb = SINB / 3sinb = 1 / 3

Two from one point______ The figure formed is called angle

According to the meaning of angle, the figure formed by two rays from a point is called angle

Two from one point______ The figure formed is called angle

According to the meaning of angle, the figure formed by two rays from a point is called angle

The figure formed by leading out () from a point is called angle
1. The figure formed by leading out () from one point is called angle.
2. A flat angle is divided into two angles according to the ratio of 4:5. The degrees of these two angles are () and ()

1. The figure formed by two rays drawn from one point is called angle
2. The degrees of these two angles are (80 degrees) and (100 degrees) respectively

The figure made up of () from a point is called angle. Angle is made up of one () or two ()

A figure formed by two rays from a point is called an angle. An angle consists of one point and two edges

Two line segments must form an angle,
Please give reasons

No,
The two line segments that make up a corner must have a common endpoint (vertex)

The graph () composed of some line segments () which are not on the same line is a polygon

A (closed) figure composed of some line segments (end to end) that are not on the same line is a polygon

1. It is known that the image of a linear function passes through two points a (- 2, - 3) and B (1,3). (1) find the analytic expression of the linear function; (2) try to judge the point
1. It is known that the image of a linear function passes through two points a (- 2, - 3) and B (1,3)
(1) Find the analytic expression of this first-order function;
(2) Try to judge whether the point P (- 1,1) is on the graph of this linear function
2. Known: function y = (2m + 1) x + (M-3)
(1) If the image of this function passes through the origin, find the value of M
(2) If the image of this function does not pass through the second quadrant, find the value range of M

Let y = KX + B bring two points into - 3 = - 2K + B3 = K + B. the solution is k = 2 b = 1, so y = 2x + 1 brings x = - 1 into y = - 1, so point P is not on this image. 2