Sin95 degree sin35 degree + cos95 degree cos35 degree

Sin95 degree sin35 degree + cos95 degree cos35 degree

Sin95 degree sin35 degree + cos95 degree cos35 degree
=Cos (95-35) degree
=Cos 60 degrees
=1/2

Sin35 ° square + cos30 ° * sin60 ° + cos35 ° square
Hope to write out the process

sin35^2+cos35^2 + cos30*sin60
=1+ 3/4
=7/4

Sin35 degrees - sin25 degrees divided by cos35 degrees - cos25 degrees calculate the correct answer to the integral

Negative radical 3

The value of sin25 ° cos35 ° - cos25 ° sin215 ° is

Original formula = sin25cos35-cos25sin (180 + 35)
=sin25cos35+cos25sin35
=sin(25+35)
=sin60
=(radical 3) / 2