Algebraic problems... Using the direct flattening method to solve equations Using direct flattening method to solve equation (1)2(x+a)^2÷3=8 (2)2(4-x)^2÷3=6 Requirements process The first wrong number should be 4

Algebraic problems... Using the direct flattening method to solve equations Using direct flattening method to solve equation (1)2(x+a)^2÷3=8 (2)2(4-x)^2÷3=6 Requirements process The first wrong number should be 4

Using direct flattening method to solve equation
(1)2(x+4)^2÷3=8；
（x+4）²=12;
x+4=±2√3;
x=-4±2√3;
(2)2(4-x)^2÷3=6
(x-4)²=9;
x-4=±3;
x=4±3;
X = 7 or 1;
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Sin7 / 5pai * cos (- 11 / 6pai) + Tan (- 15 / 4pai) * tan7 / 5pai,

sin(7/5π)cos(-11/6π)+tan(-15/4π)tan(7/5π)=sin(π+2/5π)cos(2π-1/6π)-tan(4π-1/4π)tan(π+2/5π) =-sin( 2/5π)cos(1/6π)+tan(1/4π)tan(2/5π)=-0.9511×0.8660+1×3.078≈-0.8237+3.078=2.2543

Cos (PAI / 15) × cos (2pai / 15) × cos (3pai / 15) × cos (4pai / 15) × cos (5pai / 15) × cos (6pai / 15) × cos (7pai / 15)

The original formula = [1 / (sin π / 15)], # 8226; [sin (π / 15) cos (π / 15) cos (2 π / 15).. cos (7 π / 15)] = [sin (8 π / 15) / 8sin (π / 15)], # 8226; [cos (3 π / 15) cos (5 π / 15) cos (6 π / 15) cos (7 π / 15)] =... = [sin (4 π / 5) / 2 ^ 7SiN (π / 5)] = 1 / 128 word limit