What is the arc degree of the circle angle whose arc length is equal to radius? Such as the title
If the arc length is L = a * r (a is the arc of the center angle, R is the radius of the circle), the arc of the center angle with the arc length equal to the radius is 1, and the arc of the circle angle is 1 / 2
There are many questions. Thank you first
First of all, can the set of the same angle a {a | a = β + 360 * k} with the terminal edge of an arbitrary angle β be understood as rotating K cycles and then rotating a β with the positive half axis of X as the starting edge? For example, K is a negative integer and β is a positive angle. Does it mean rotating K cycles clockwise and then rotating a β anticlockwise?
2. As for the comparison of angles, if two positive angles compare, is it a direct comparison of degrees, but how about two positive angles? One positive angle and one negative angle?
3. About a quadrant angle, such as the first quadrant angle, why is {a | 360K
1. That's understandable. Absolutely right
2. A simple angle comparison is the same as a real number comparison. A positive angle is greater than all negative angles
The difference between angle and trigonometric function of angle is
3. At this time, a is no longer in the range of 0-360 degrees
It can only be {a | 360K
How to prove the cubic power of sin3x = 3sinx + 4 (SiNx)
sin3x
=sin(x+2x)
=sinx*cos2x+cosx*sin2x
=sinx(1-2sinx^2)+cosx*2sinx*cosx
=sinx-2sinx^3+2sinx*(1-sinx^2)
=3sinx-4sinx^3