What is Tan (- 900 + 45)?
Tan (multiple of 180) all = 0
So tan (- 900 + 45) = Tan (180 * (- 5) + 45) = Tan 45 = 1
Calculation: Tan 45 °· cos 30 ° - Tan 30 ° + cos 60 °
The original formula is 1 × 32-33 + 12 = 36 + 12
First simplify and then evaluate (a + b) & sup2; + (a-b) × (2a + b) - 3A & sup2, where a = - 2 - √ 3, B = √ 3-2
(a+b)² +(a-b)×(2a+b)-3a²
=a²+2ab+b²+2a²-ab-b²-3a²
=ab
=(-2-√3 )(√3-2)
=1
Elementary simplification evaluation: given: 2x-3 = 0, find the value of algebraic formula (1 + x) (1-x) + (x + 2) & sup2; - (x + 1) (2x-3)
(1+x)(1-x)+(x+2)²-(x+1)(2x-3)=1-x²+x²+4x+4-(2x²-x-3)=1-x²+x²+4x+4-2x²+x+3=-2x²+5x+8=-2x*x+5x+8=-3x+5x+8=2x+8=3+8=11
Factorization: 3a3-12a2 + 12a=______ .
The original formula is 3A (a2-4a + 4) = 3A (A-2) 2, so the answer is 3A (A-2) 2
(A & sup2; - 4A) & sup2; + (3a-12) & sup2; factorization
(a^2+9)(a-4)^2
(A's Square plus 9) * (a minus 4's Square)
If (2x + y-4) 2 and | 3x-5y-12 | are opposite numbers, then x + y=______ .
∵ (2x + y-4) 2 and | 3x-5y-12 | are opposite numbers, ∵ (2x + y-4) 2 + | 3x-5y-12 | = 0, while (2x + y-4) 2 and | 3x-5y-12 | are non negative numbers, ∵ (2x + y-4) 2 = 0, | 3x-5y-12 | = 0, ∵ 2x + y − 4 = 03x − 5Y − 12 = 0, ∵ x = 3213, y = - 1213, ∵ x + y = 2013
Sin, cos, Tan, cot of 37 and 53
sin37°=0.6
cos37°=0.8
tan37°=0.75
cot37°=1.33
sin53°=0.8
cos53°=0.6
tan53°=1.3
cot53°=0.75
What are sin, Tan, cos, 0.30.45.60.90.120.135.150.180 degrees?
0 30 ° 45 ° 60 ° 90 ° 120 ° 135 ° 150 ° 180 ° SiNx 0 1 / 2 √ 2 / 2 √ 3 / 2 1 √ 3 / 2 √ 2 / 2 1 / 20 cosx 1 √ 3 / 2 √ 2 / 2 1 / 20 - 1 / 2 - √ 2 / 2 - √ 3 / 2 - 1 TaNx 0 √ 3 / 3 1 √ 3 does not exist - √ 3 - 1 - √ 3 / 3 0
If sin θ = m | M|
Because sin θ = m | M|