Square of X + 1 / 4x-8 = 0 First order equation of the second hospital

Square of X + 1 / 4x-8 = 0 First order equation of the second hospital

The equation can be reduced to x square + 2 * 1 / 8 * x + 1 / 8 square = 63 / 64 (x + 1 / 8) square = 63 / 64, so X1 = 8 / 8 root 63 minus 1 {(- 1 + root 63) / 8} x2 = - 8 root 63 minus 1 {(1 + root 63) / - 8}

The square of X - 4x + 1.5 = 0

X square-4x + 1 = 0,
∴x-4+1/x=0;
x+1/x=4;
∴x²+1/x²=(x+1/x)²-2=16-2=14;
Root x square + 1 / 2 of x minus 5 = √ (14-5) = 3;
If you don't understand this question, you can ask,

Xsquare + 1 / 4x-xsquare-2 / 4x = 0

1/x(x+4)-2/x(x-4)=0
Multiply both sides by X (x + 4) (x-4)
(x-4)-2(x+4)=0
x-4-2x-8=0
x=-12
After testing, x = - 12 is the solution of the equation

Y = the square of x-4x-5 what do you get
The more, the better

Y = the square of x-4x-5
=X²－4X-5
=（X-5）（x+1）
=（X-2）²-3²

What is the factorization factor of 4 square of X - 4 square of X + 4 X-1

4 square of X - 4 square of X + 4x-1
The fourth power of X is represented by x ^ 4
X ^ 2 is the square of X
x^4-4x^2+4x-1
=x^4-(4x^2-4x+1)
=(x^2)^2-(2x-1)^2
=[x^2+(2x-1)][x^2-(2x-1)]
=(x^2+2x-1)(x^2-2x+1)
=（x^2+2x-1)(x-1）²

Factorization factor: xsquare-ysquare-4x-4
It's the question of Harbin high school entrance examination in 2006!

Brother, I think you are wrong. It should be x square - y square - 4x + 4
x^2-y^2-4x+4
=(x-2)^2-y^2
=(x-2+y)(x-2-y)

Square of X + 4x = minus 4 factorization

x²＋4x＝﹣4
x²＋4x＋4＝0
﹙x＋2﹚²＝0
x1＝x2＝﹣2.

Write out the solution set of the following inequality: ① 2x + 6 > 3x-8; ② X & # 178; + 4x-5 ≥ 0

①2x+6＞3X-8
2x-3x＞-8-6
-x＞-14
x

Help me find the solution set of high school inequality: 13-4x square > 0 solution set. Please
Finding the solution set of inequality: the square of 13-4x > 0

-Root of two 13

Finding the solution set of inequality-x ^ 2 + 4x + 5
2. Find function definition field: y = (√ X-1 / x + 2) + 5

x²-4x-5>0
(x-5)(x+1)>0
Ψ x > 5 or X