The square of 9x (x-3) - 36x

The square of 9x (x-3) - 36x

9x(x-3)-36x=0
x(x-3-4)=0
x(x-7)=0
x1=0,x2=7

24x square y × 36x square Y 7 / 2

Solution
24x & # 178; y × (7 / 36x & # 178; Y & # 178;) - this one
=(24×7/36)[x²y×(1/x²y²)]
=14/(13y)

Using factorization method to solve the following equation (x-3) - 3 (3-x) - 4 = 0

(x-3)²+3(x-3)-4=0
(x-3+4)(x-3-1)=0
(x+1)(x-4)=0
x=-1,x=4

Using factorization method to solve equation 4 (X-2) square = x (X-2)

Square of 4 (X-2) = x (X-2)
Square of 4 (X-2) - x (X-2) = 0
(x-2)(4x-8-x)=0
(x-2)(3x-8)=0
x1=2 x2=8/3

The square of 36x, the square of Y - 12xy + 1

=(6xy-1)²

Square of (2x-3) = 25
Square of (2x-3) = 25 find the value of X

Square of (2x-3) = 25
2x-3=±5
2x=3±5
2X = 8 or 2x = - 2
X = 4 or x = - 1

Ask a math problem: the square of a - 5A + 1 = 0. Ask the square of a + one-third of the square of A
This is a problem in the second half of the first semester of junior high school

Solution
Because a & sup2; - 5A + 1 = 0
Divide both sides by A,
a-5+1/a=0
a+1/a=5
Square on both sides
a²+2+1/a²=25
therefore
a²+1/a²=25-2=23

How to do the square of half x plus 5 minus the square of half x minus 5?

X-0.36x = 16

How to solve x + 0.36x = 16

x+0.36x=16
1.36x=16
x=16/1.36
x=200/17
x=11.76