A simple and convenient method for the determination of 8.9 × 1.2-8.9

A simple and convenient method for the determination of 8.9 × 1.2-8.9

8.9×1.2-8.9
=8.9×（1.2-1）
=8.9×1.1
=8.9×（1+0.1）
=8.9+0.89
=9.79

How to do 201 * 24 in a simple way

201x24
=(200+1)x24
=200x24+24
=4800+24
=4824

1 / 5 + 7 / 15 + 4 / 15 7 / 10 - (3 / 4-2 / 5) 1-7 / 15-2 / 5 13 / 15 - (1 / 3 + 2 / 5)
1-3/10-2/5 5-3/7+4/7 23/24-1/6-3/8 4/9+1/10+5/9 1/12+3/8+11/12+5/8 1-（3/11-5/9）
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1 / 5 + 7 / 15 + 4 / 15 = 3 / 15 + 7 / 15 + 4 / 15 = 14 / 157 / 10 - (3 / 4-2 / 5) = 7 / 10-3 / 4 + 2 / 5 = 14 / 20-15 / 20 + 8 / 20 = 7 / 20 1-7 / 15-2 / 5 = 1 - (7 / 15 + 6 / 15) = 1-13 / 15 = 2 / 1513 / 15 - (1 / 3 + 2 / 5) = 13 / 15-5 / 15-6 / 15 = 2 / 15 5-3 / 7 + 4 / 7 = 5-1 / 7 = 4 and 6 / 7 23 / 24-1 / 6 -

3 / 4 + 7 / 15 + 8 / 15 =? Simple calculation

Original title = 3 / 4 + (7 + 8) / 15 = 1 and 3 / 4

Simple calculation method of 7.34 + 8.90-3.34

=7.34-3.34+8.90
=4+8.9
=12.9

How to calculate (- 5) x (+ 7 1 / 3) + 7x (- 7 1 / 3) - (+ 12) X7 1 / 3

(- 5) x (+ 7 / 3) + + 7) x (- 7 / 3) - (+ 12) X7 / 3
=-5x7 1 / 3-7x7 1 / 3-12x7 1 / 3
=-(5 + 7 + 12) X7 and 1 / 3
=-24x7 and 1 / 3
=-1 / 24x7-24x3
=-168-8
=-176

How to calculate 2.4 △ 0.25

2.4÷0.25
＝2.4/1*4
＝9.6

It is known that the minimum period of the function y = sin (2wx - π / 6) + 0.5 (W > 0) is π
(1) Finding the value of W
(2) Finding the value range of function y in the interval [0,2 π / 3]

1. The minimum period T = 2 π / 2W = π, w = 1;
2. From 1, y = sin (2x - π / 6) + 0.5 (W > 0),
Because if it's on (0, π), - 1

If f (x) = sin ^ 2wx + root 3sinwxcoswx, X belongs to R, f (a) = - 1 / 2, f (b) = 1 / 2, and the minimum value of | A-B | is equal to 3 π / 4, then the value of positive number W is

If f (x) = Sin & sup2; Wx + (√ 3) sinwxcoswx = (1-cos2wx) / 2 + (√ 3 / 2) sin2wx = sin2wxcos π / 6-cos2wxsin π / 6 + 1 / 2 = sin (2wx - π / 6) + 1 / 2, let g (x) = sin (2wx - π / 6), then when f (a) = - 1 / 2, G (a) = - 1; when f (b) = 1 / 2, G (b) = 0 and G (x) image is in the trough, G (x) = -

What is the minimum period T of function y equal to sin (x + Wu / 3) sin (x + Wu / 2)

Y = sin (x + 1 / 3 Wu) sin (x + 1 / 2 Wu) = - 1 / 2 [cos (2x + 5 π / 6) - cos (- π / 6)] so t = 2 π / w = 2 π / 2 = π