How about 53 × 57

How about 53 × 57

50×60 +3×7 =3021,

Given: X (x-1) - (2 of X-Y) = - 2, find the value of (2 of X + 2 of Y) divided by 2-xy
2-7 (x-5y) - 8 of factorization (x-5y)
It is known that: x + y = 1, xy = - 1 / 2, the value of the two sides of X (x + y) (X-Y) - x (x + y) can be obtained by factorization
The first step is to add, subtract, multiply and sum of squares of the two input numbers to get four numbers, the second step is to multiply the four numbers, and the third step is to output the number
(1) If the two input numbers are x and Y respectively, please use the polynomial of X and y to express the output result;
(2) If the two input numbers are 3 and 2 respectively, what is the output result?

x(x-1)-(x^2-y)=-2
x^2-x-x^2+y=-2
y-x=-2
(x^2+y^2)/2-xy
=(y^2-2xy+x^2)/2
=(y-x)^2/2
=(-2)^2/2
=2
(x-5y)^2-7(x-5y)-8
=[(x-5y)-8][(x-5y)+1]
=(x-5y-8)(x-5y+1)
x+y=1,xy=-1/2
x(x+y)(x-y）-x(x+y)^2
=x(x+y)(x-y-x-y)
=-2xy(x+y)
=-2*(-1/2)*1
=1
The first step is to add, subtract, multiply and sum of squares of the two input numbers to get four numbers, the second step is to multiply the four numbers, and the third step is to output the number
(1) If the two input numbers are x and Y respectively, please use the polynomial of X and y to express the output result;
(x+y)(x-y)*(xy)*(x^2+y^2)
=xy(x^2-y^2)(x^2+y^2)
=xy(x^4-y^4)
=x^5y-xy^5
(2) If the two input numbers are 3 and 2 respectively, what is the output result?
(3+2)*(3-2)*(3*2)*(3^2+2^2)
=5*1*6*13
=390

A total of 18 bicycles and tricycles are parked in front of the mall, with a total of 40 wheels. How many bicycles and tricycles do you have? Give it a try
I'll give you a reward of 30,
Bicycles
Tricycle
Number of rounds

Bicycle (18) (17) (16) (15) (14) (13) (12) (11) (10)
Tricycle (0) (1) (2) (3) (4) (5) (6) (7) (8)
Number of rounds (36) (37) (38) (39) (40) (41) (42) (43) (44)
So it's 14 bicycles. Four tricycles