The square plus ax minus B of the quadratic equation x with real coefficients is equal to zero, one root is between (0,1), one root is between (1,2), and a (0,2) 2) P (a, b), find the value range of the module of 0A vector multiplied by 0P vector △ 0P vector

The square plus ax minus B of the quadratic equation x with real coefficients is equal to zero, one root is between (0,1), one root is between (1,2), and a (0,2) 2) P (a, b), find the value range of the module of 0A vector multiplied by 0P vector △ 0P vector

1)1

It is known that the image of the proposition p: function y = x2 + ax + 4 has no common point with the X axis, and the proposition q: a2-4a-5 ≤ 0. If the proposition p Λ q is true, the value range of the real number a is obtained

If proposition p Λ q is true proposition, then proposition p: the image of function y = x2 + ax + 4 has no common point with X axis, which is true proposition; then △ = a2-16 < 0, then - 4 < a < 4; proposition q: a2-4a-5 ≤ 0, which is true proposition; then - 1 < a < 5; then - 1 < a < 4

Factorization (AX by) ^ 3 + (by CZ) ^ 3 - (AX CZ) ^ 3

（ax-by)^3+(by-cz)^3-(ax-cz)^3=(ax-by+by-cz)[(ax-by)²-(ax-by)(by-cz)+(by-cz)²]-(ax-cz)³=(ax-cz)[(ax-by)²-(ax-by)(by-cz)+(by-cz)²-(ax-cz)²]=(ax-cz){(ax-by)²-(ax-by)(b...