What is the high flame retardant tape for wires and cables? How to use it? What are the structures of ZA, ZB and ZC flame retardant parts?

What is the high flame retardant tape for wires and cables? How to use it? What are the structures of ZA, ZB and ZC flame retardant parts?

It may be the wrapping tape after insulation. The wrapping tape with mica tape has a certain flame retardant effect
ZA, ZB and ZC only indicate different flame retardant grade, not necessarily any inherent structure
Different forms of the same material may be able to reach ZA, ZB and ZC levels, which belongs to the enterprise process secrets
There are three ways to improve flame retardancy
1. Use special flame retardant materials
2. Add flame retardant materials into PVC and XLPE insulation materials
3. Use armor. This may be what you said to achieve flame retardant effect through structural adjustment

As shown in the figure, given OP = (2,1), OA = (1,7), OB = (5,1), let Z be a moving point on the straight line op. find oz when Za * ZB is the minimum
It's all vector problems

(1) Let the vector oz = (x, y), then Za = (1-x, 7-y), ZB = (5-x, 1-y)
And point Z is on the line OP, where K (oz) = Y / x = 1 / 2 = K (OP)
The vector ZA. The vector ZB = (1-x) (5-x) + (7-y) (1-y)
=5-6x+x^2+7-8y+y^2
=5-12y+4y^2+7-8y+y^2
=12-20y+5y^2
=5(y-2)^2-8
≥-8
If and only if y = 2 and x = 4, the minimum value - 8 is obtained
The vector oz = (4,2)
(2) ∵ vector ZA. Vector ZB = | ZA | * | ZB | * cos ∠ AZB
| cos ∠ AZB = vector ZA. Vector ZB / (| ZA | * | ZB |)
While | ZA | = | (1-4,7-2) | = √ 34, | ZB | = | (5-4,1-2) | = √ 2,
Vector ZA. Vector ZB min = - 8
∴cos∠AZB=-8/(√34*√2)=-4/√17

Given | X - 6 | + | 3Y - 8 | + | Z - 2 | = 0, find the value of the algebraic formula x + 3Y + Z

Because the absolute value of a number is greater than or equal to 0
So the equation holds only when X - 6 = 0 and 3Y - 8 = 0 and Z - 2 = 0
So x = 6, 3Y = 8, z = 2
So x + 3Y + Z
= 6 + 8 + 2
= 16