Given | x-3 | + | 2y-8 | + | Z-2 | = 0, find the value of the algebraic formula x + 3y-z

Given | x-3 | + | 2y-8 | + | Z-2 | = 0, find the value of the algebraic formula x + 3y-z

It is known that | x-3 | + | 2y-8 | + | Z-2 | = 0
So x-3 = 0, 2y-8 = 0, Z-2 = 0
So x = 3, y = 4, z = 2
So x + 3y-z = 3 + 3 * 4-2 = 13
If you don't understand, please hi me, I wish you a happy study!

If x-3y = - 3, then the value of 5-x + 3Y is ()
A. 0B. 2C. 5D. 8

∵ x-3y = - 3, ∵ 5-x + 3Y = 5 - (x-3y) = 5 - (- 3) = 8

If x-3y = - 3, then the value of 5-x + 3Y is ()
A. 0B. 2C. 5D. 8

∵ x-3y = - 3, ∵ 5-x + 3Y = 5 - (x-3y) = 5 - (- 3) = 8