(x+3):(2y-1):(z\2+2)=2:3:4 3-2y+z=8

(x+3):(2y-1):(z\2+2)=2:3:4 3-2y+z=8

That is, (x + 3) / 2 = (2y-1) / 3 = (Z / 2 + 2) / 4
Let a = (x + 3) / 2 = (2y-1) / 3 = (Z / 2 + 2) / 4
x=2a-3
y=(3a+1)/2
z=8a-4
3x-2y+z=8
So 6a-9-3a-1 + 8a-4 = 8
11a=22
a=2
therefore
x=1
y=7/2
z=12

The solution set of equation X-6 = O
The solution set of inequality X-1 ＜ 0 X & # 178; + 2 = 0 solution set of equation x & # 178; - 5x-6 = 0

The solution set of the equation X-6 = 0o is {x L x = 6}
The solution set of equation x & # 178; + 2 equal to 0 is empty
The solution set of inequality X-1 < 0 is {x L x}

If the complex number Z = I-2, then the corresponding points of its conjugate complex number in the complex plane lie in several quadrants

The third quadrant, conjugate-i-2

Which quadrant of the complex plane is the point corresponding to the conjugate complex z = - 1-I?

The conjugate complex number is Z = - 1 + I, so the corresponding point coordinate is (- 1,1) in the second quadrant