4A ^ 2-4a (B + C) + (B + C) ^ 2 factorization

4A ^ 2-4a (B + C) + (B + C) ^ 2 factorization

4a^2-4a(b+c)+(b+c)^2
=[2a-(b+c)]^2
=(2a-b-c)^2

How to factorize 4A ^ 2-B ^ 2-4a + 1~
4A square-b square-4a + 1

＝4a^2-4a+1-b^2
=(2a-1)^2-b^2
=(2a-1-b)(2a-1+b)

Factorization (detailed process): 4A ^ 2-B ^ 2
-25x^2+4
a^4-81
4(x+1)^2-9
(3x+2y)^2-(2x+3y)^2
x^2(a-1)+4(1-a)

4a^2-b^2=（2a+b)(2a-b)-25x^2+4=(2+5x)(2-5x)a^4-81=(a^2+9)(a^2-9)=(a^2+9)(a+3)(a-3)4(x+1)^2-9=(2x+2+3)(2x+2-3)=(2x+5)(2x-1)(3x+2y)^2-(2x+3y)^2=(3x+2y+2x+3y)(3x+2y-2x-3y)=(5x+5y)(x-y)=5(x+y)(x-y)x^2(a-1...