Given the function f (x) = 2 ^ (x + 3), the image of y = g (x) is symmetric with respect to the straight line y = X. if Mn = 16 (M > 0, n > 0), then the value of G (m) + G (n) is the same Given the function f (x) = 2 ^ (x + 3), the image of y = g (x) is symmetric with respect to the line y = X. if Mn = 8 (M > 0, n > 0), then the value of G (m) + G (n) is?

Given the function f (x) = 2 ^ (x + 3), the image of y = g (x) is symmetric with respect to the straight line y = X. if Mn = 16 (M > 0, n > 0), then the value of G (m) + G (n) is the same Given the function f (x) = 2 ^ (x + 3), the image of y = g (x) is symmetric with respect to the line y = X. if Mn = 8 (M > 0, n > 0), then the value of G (m) + G (n) is?

If Mn = 8 (m ﹥ 0, n ﹥ 0), then the value of G (m) + G (n) is? F (x) and G (x) are reciprocal functions. From y = 2 ^ (x + 3), x + 3 = log ﹥ 8322; y, that is, x = (log ﹥ 8322; y) - 3, exchange x, y, that is, inverse function g (x) = (log ﹥ 832

The image of inverse scale function y = - K / X is shown in the figure. Point m is the point on the function image, Mn ⊥ X axis, and the perpendicular foot is point n. if △ mon = 2, then the value of K is ()
The image of inverse scale function y = - K / X is shown in the figure. Point m is the point on the function image, Mn ⊥ X axis, and the perpendicular foot is point n. if △ mon = 2, then the value of K is ()
A.2 B.-2 C.4 D.-4

I can't see the graph, so I can only say either 4 or - 4. Because the expression of inverse scale function is y = K / X (K ≠ 0), so xy = K
And s triangle mon = 2, so xy = 2 × 2 = 4
If the image is in one or three quadrants and K is - 4, select D
If the image is in quadrant two or four and K is 4, select C

Function F X = NX + 1 / 2x + m Mn ≠ 2
Function f (x) = (NX + 1) / (2x + m), (Mn ≠ 2)
If f (x) * f (1 / x) = k
① Find the value of K;
② Given f [f (1)] = K / 2, find f (x)

According to f (x) = (NX + 1) / (2x + m), we get f (1 / x) = (x + n) / (MX + 2), so f (x) * f (1 / x) = (NX + 1) / (2x + m) × (x + n) / (MX + 2) = [NX & sup2; + (n & sup2; + 1) x + n] / [2mx & sup2; + (M & sup2; + 4) x + 2m], find the value of K, K is a constant

Given the linear function y = m + 5 x + 2-N, when the value of Mn satisfies what condition, the intersection of the image of the given function and the image of y = - x + 1 is on the X axis?

The intersection of the image of the function and the image of y = - x + 1 is on the X axis
When y = 0, x = 1
That is, the function passes the point (1,0)
Take the point (1,0) into the linear function y = m + 5 x + 2-n
0=m+5+2-n
m-n=-7

According to the plan, the area of the industrial park is (a + 3b) &# 178; square meters, while there is an abandoned brick kiln in the suburb, with an area of (A & # 178; + 9b & # 178;) square meters. Adjacent to the brick kiln, there are two rectangular pits left by the former brick kiln, which are 3A meters long and B meters wide, I want to fill these two pits and build this industrial park here. Does the area of this industrial park conform to the planning rules

a²+9b²+2*3ab=a²+（3a）²+6ab=(a+3b）²
It's a complete square formula~
I hope you can understand. I'm also a sophomore~

The more problems, the better

Well, I'll give you a few
a³-4a
2x²-12x+18
(2a-b)²+8ab
25(m＋n)²-4(m＋n)²
xy-x-y+1
x³+6x²-27x
¼x+x³-x²
x²-4y²+2x-4y
Calculation by simple method
100/(99²+198+1)
198²-396×98+98²
Integral multiplication and division are relatively simple, you do these first, if you need big words, there are many more difficult!

The first problem of integral multiplication and division and factorization
1. Simplification
（1）(2a+1)(-a-2)+a(2-a)
(2)[(x+y)²-(x+y)(x-y)]÷(-2-y)
2. Factorization
-2x³+8xy²
3. Given X & sup2; - 2x = 2, find the value of the algebraic formula (x-1) & sup2; + (x + 3) (x-3) + (x-3) (x-1)

1. Simplify (1) (2a + 1) (- A-2) + a (2-A) = (- 2A & sup2; - 5A - 2) + (2A - A & sup2;) = - 3A & sup2; - 3a-2 (2) [(x + y) & sup2; - (x + y) (X-Y)] / (- 2-y) = [(X & sup2; + 2XY + Y & sup2;) - (X & sup2; - Y & sup2;)] / [(y + 2)] = - [2Y & sup2; + 2XY

Factorization and integral multiplication and division
1）2X×12x³
2）（a+b)-1
3)121x²-9y²2²
4）x²-12x+16
5）a²b²-6ab+9
6）1/9m²+1-2/3m
7）(x²+y²)²-4x²y²
8)ac²(2b+3c)²-ab²(3c+2b)²
9) (a-b)²-2ab(a-b)
10) (x²-3)²+2(3-x²)+1

1）2X×12x³
=24X^4
2）（a+b)-1
=a+b-1
3)121x²-9y²2²
=121x²-36y²
=(11X)²-(6y)²
=(11X+6y)(11X+6y)
4）x²-12x+16
=x²-8x+4²-4x
=(x-4)²-4x
5）a²b²-6ab+9
=(ab)²-6ab+3²
=(ab-3)²
6）1/9m²+1-2/3m
=1/(3m)² -2/3m +1
=(1/3m - 1)²
7）(x²+y²)²-4x²y²
=(x²+y²)²-(2xy)²
=[(x²+y²)-2xy][(x²+y²)+2xy]
=(x-y)²(x+y)²
8)ac²(2b+3c)²-ab²(3c+2b)²
=2abc²+3ac³-3ab²c-2ab³
=(2abc²-2ab³)+(3ac³-3ab²c)
=2ab(c²-b²)+3ac(c²-b²)
=(c²-b²)(2ab+3ac)
=(c+b)(c-b)(2ab+3ac)
9) (a-b)²-2ab(a-b)
=(a-b)(a-b-2ab)
10) (x²-3)²+2(3-x²)+1
=(x²-3)²-2(x²-3)+1
=[(x²-3)-1]²
=(x²-4)²
=[(x+2)(x-2)]²

Junior two on mathematics, a few factorization problems, to have a detailed problem-solving process
(1)a²（a-b)+b²(b-a）
(2)（x-1)(x-3)+1
(3)(x+y)²-4(x+y-1)
(4)ax-bx+ay-by

(1)a²（a-b)+b²(b-a）=（a-b)(a²-b²）=（a-b)²（a+b)2)（x-1)(x-3)+1=x²-4x+3+1=x²-4x+4=(x-2)²3)(x+y)²-4(x+y-1)=(x+y)²-4(x+y）+4=（x+y-2)²4)ax-bx+ay-b...

I given a + B + C = 0, a ^ 2 + B ^ 2 + C ^ 2 = 0.1, find the value of a ^ 4 + B ^ 4 + C ^ 4
005
II A + B + 2C = 1 A ^ 2 + B ^ 2-8c ^ 2 + 6C = 5 AB BC CA
-2
Don't say anything else.