Let u = {positive integer no more than 5}, a = {x | x2-5x + q = 0}, B = {x | x2 + PX + 12 = 0}, (∁ UA) ∪ B = {1, 3, 4, 5}, find P, Q and set a, B

Let u = {positive integer no more than 5}, a = {x | x2-5x + q = 0}, B = {x | x2 + PX + 12 = 0}, (∁ UA) ∪ B = {1, 3, 4, 5}, find P, Q and set a, B

The complete set u = {1,2,3,4,5}, a = {x | x2-5x + q = 0}, B = {x | x2 + PX + 12 = 0}, (∁ UA) ∪ B = {1,3,4,5}, ∪ 2 ∈ a, substituting x = 2 into x2-5x + q = 0, we get: 4-10 + q = 0, namely q = 6, namely x2-5x + 6 = 0, ∁ X-2) (x-3) = 0, namely x = 2 or x = 3, ∁ a = {2,3}, ∁ UA = {1,4

Let u = R, a = 1 ≤ x ≤ 2, if bu (CUA) = R, B ∩ (CUA) = 0

∵A={x|1≤x≤2}
∴CuA={x|x2}
∵BU(CuA)=R,B∩(CuA)={x|0

Let u = R, a = (x | x > 3), then what is CUA

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