How to do 9x & # 178; + 6x + 1 > 0

How to do 9x & # 178; + 6x + 1 > 0


Because Δ = B ^ 2-4ac = 6 * 6-4 * 9 * 1 = 0
So x = [- B ± root (b ^ 2-4ac)] / 2A = - 6 / 2 * 9 = - 1 / 3
When x = - 1 / 3, there is a unique intersection (- 1 / 3,0) with y axis
When x is not equal to - 1 / 3, y = 9x & # 178; + 6x + 1 > 0