Solving the system of quadratic equations with two variables -5x + 3 / 11y = 16 and 3 / 11x + (- 5Y) = 1 need a process. Thank you

Solving the system of quadratic equations with two variables -5x + 3 / 11y = 16 and 3 / 11x + (- 5Y) = 1 need a process. Thank you

The sum of the two formulas (11-5 / 3) x + (11-5y / 3) = 17 - 4 / 3 (x + y) = 17 x + y = - 51 / 4 x = - 51 / 4-y
Substituting (1) formula 251 + 5Y + 11y / 3 = 16 26y / 3 = - 235 y = - 705 / 26 x = - 51 / 4 + 705 / 26

The solution of a system of linear equations with two variables
x+y=95
2x(1-2/3)=y(1-40%)
Please write step by step. I can't work it out

{x + y = 95 (1) {2x (1-2 / 3) = y (1-40%) (2) finishing (2) to get 2x × 1 / 3 = y × 60% (2 / 3) x = (6 / 10) y 10x = 9y (3) from (1) to get x = 95-y (4) substitute (4) into (3) 10 × (95-y) = 9y 950-10y = 9y 950 = 19y y y = 50 substitute y = 50 into x = 95-y x = 95-50 = 45

Xiaoming's family contracted an orchard. Last year, the balance of the orchard was 12000 yuan. This year's fruit harvest is good. It is estimated that the income can be increased by 20% compared with last year. Moreover, due to the improvement of planting technology, the expenditure will be reduced by 10% compared with last year. In this way, the balance of this year will be 11400 yuan more than last year

Let Xiaoming family's income and expenditure of planting fruit last year be X Yuan and Y yuan respectively. According to the theme, X − y = 12000 (1 + 20%) x − y = 12000 + 11400, and the solution is x = 42000y = 30000. Therefore, Xiaoming family's income and expenditure of planting fruit this year are 1.2 × 42000 = 50400 (yuan) and 0.9 × 30000 = 27000 (yuan). Answer: Xiaoming family's income and expenditure of planting fruit this year are 50400 yuan and 27000 yuan respectively