Given the kinematics equation of a particle, how to find the trajectory equation of a particle?

Given the kinematics equation of a particle, how to find the trajectory equation of a particle?

Establish a coordinate system, take a special point as the origin, and turn the problem into a pure mathematical problem

If the kinematics equation of a particle moving in a straight line is x = 3t-5t ^ 3 + 6 (SI), then the particle moves in a straight line
A. The acceleration is in the positive direction of x-axis
B. The acceleration is in the negative direction of x-axis
C. The acceleration is in the positive direction of X axis
D. The acceleration is in the negative direction of x-axis

Now high school stage learned calculus preliminary, such a problem can be analyzed
The first derivative of X to time is velocity, v = 3-15t & # 178;,
The acceleration is obtained by deriving the time, a = - 30t
The direction of acceleration is opposite to the positive direction, that is, along the negative direction of X axis, and its magnitude changes with time,
So choose D

Chemical formula, name and cluster valence of compounds composed of O, Na and Si
Such as the title

Na2SiO3 sodium silicate (si03) 2-silicate-2 valence

Please tell me the solution of binary linear equations
Q please
Tell me the solution of binary linear equations!]
I hope I can make it clear. It's my first contact
Well said,

For example 1, the equation X-Y = 3 is solved by the method of bringing in. For example 2, the coefficient of X in equation 1 is one, and the formula containing y is used to express y. for example 1, x = y + 3 is obtained. For example 3 (y + 3) - 8y = 14 is obtained by substituting 3 (y + 3) - 8y = 14

What is the relationship between the equation of first degree and the equation of second degree?

One variable equation of first degree and one variable equation of second degree
The same thing: there is an unknown,
Difference: the number of unknowns is different,
Connection: when solving a quadratic equation of one variable, it should be transformed into a quadratic equation of one variable to solve it, (reduce the degree)

It is difficult for me to find out the equivalent relationship between solving the first-order equation of one variable and practical problems, or solving the first-order equation of two variables, and the second-order equation of one variable and practical problems

We need to find out exactly how many variables there are
We should also have some life experience
For example, if you ask profit y, the cost is 5 yuan, the selling price is 7 yuan, and X items are sold, you should know that profit = total sales - total cost
Then y = 7x-5x = 2x

What is the relationship between binary linear equations and unitary linear equations? How to solve binary linear equations

Through the addition and subtraction method to eliminate the binary inside to the element, so as to become a unary equation can be solved

Help to solve the linear equation of one variable and the system of linear equations of two variables
-2/X=1-X
x+y=30000
x/7900+y/500=40

-2/X=1-X
If both sides of Fangcheng are multiplied by X at the same time, then
-2=x-x^2
x=2
x+y=30000 1
x/7900+y/500=40 2
From 1, x = 3000-y
Substituting x = 3000-y into 2, we get
3000-y/7900+y/500=40
Let's figure out the answer~
I'm kind enough

Can two linear equations of one variable form a system of linear equations of two variables
For example, x + 2 = 1 and
3-y=2

Put 3-y = 2 into x + 2 = 1, and change it into x + 3-y = 1. You see, there is a 2 in the first test, and there is also a 2 in the second formula, which is an equivalent. This kind of problem is easy to do as long as you find an equivalent

First order equation of one variable, first order equation of two variables, first order equations of one variable, first order equations of two variables,

There is no system of linear equations of one variable, but a linear equation of two variables has innumerable solutions. 1. Linear equations of one variable: (1), x + 3 = 1 (2); - (?) 190; X = 3 / 2 (3). 2-3x = - 1 (4). 2 / 3x-5 = 1 (5). 1 / 4x + 5 / 4 = - 4 (6). - x + 0.5x = 1 (7) 3x-1 = - 4 (8). 4x-6 = 3x-8 (9). 6 = 3-5x2, linear equations of two variables