Let f (2x + 1) = 4x square + 4x. Find the analytic formula of F (x)

Let f (2x + 1) = 4x square + 4x. Find the analytic formula of F (x)

F (2x + 1) = 4x square + 4x
2x+1=t
2x=t-1
f(t)=(t-1)^2+2(t-1)=t^2-1
Replace T with X
f(x)=x^2-1

If f (2x + 1) = the square of X + 4x, what is the analytic expression of F (x)

Law 1: the exchange yuan act t = t = 2x + 1, then x = (t-1) / 2F (T) is x = (t-1) / 2F (T) (x = (t-1) / 2 (t-1) / 2 = (t-1) / \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\+ 1 +

Solve the following equation, find the sum of two equations and the square of product (1) x - 3x = 15 (2) 5x - 1 = 4x + X

Weida Theorem
(1)x1+x2=3; x1x2=-15
(2) Is it (5x) & 178; or 5x & 178;? I'll take the latter
x1+x2=1; x1x2=-1

Given x 2 + y 2-4x + 6y + 13 = 0, find the value of X 2-6xy + 9y 2

∵ x2 + y2-4x + 6y + 13 = (X-2) 2 + (y + 3) 2 = 0, ∵ X-2 = 0, y + 3 = 0, that is, x = 2, y = - 3, then the original formula = (x-3y) 2 = 112 = 121

Equation 7.8x + 2.4x = 1

7.8x+2.4x=1.08
（7.8+2.4）x=1.08
10.2x=1.08
x=1.08÷10.2
x=108/1020
x=9/85

3 / 8x + (x-3 / 8x) × 2 / 3 + 55 = x + 1 / 4x solved by equation
3 / 8x + (x-3 / 8x) × 2 / 3 + 55 = x + 1 / 4x solved by equation

3/8x+（x-3/8x）×2/3+55=x+1/4x
3/8x+5/12x+55=5/4x
11/24x=55
x=120

8x-27.54 ÷ 2.7 = 1.8 to solve the equation

8x-27.54/2.7-1.8 solving the equation
8x-27.54/2.7=1.8

8x-27.54/2.7=1.8
21.6x-27.54=4.86
21.6x=32.4 x=1.5

Solving equation 8x-27.54 △ 2.7 = 1.8

8x-27.54=1.8×2.7
8x-27.54=4.86
8 x=32.4
x=4.05

8x + 10 * 1.1 = 15.8 [equation]

8x+10*1.1=15.8
8x=15.8-11=4.8
x=4.8/8=0.6