A pile of loess is shown in the figure below. The area of a is 25 square meters, the area of B is 15 square meters, and H is 4 meters. Now we need to push the soil at a to B, which is the same height as a and B, and the area of a has dropped by several meters? (hint: solve the equation)

A pile of loess is shown in the figure below. The area of a is 25 square meters, the area of B is 15 square meters, and H is 4 meters. Now we need to push the soil at a to B, which is the same height as a and B, and the area of a has dropped by several meters? (hint: solve the equation)

Let a drop x meters
25*x=15(4+x)
25x=60+15x
10x=60
X = 6 m, 6 divided by 4 equals 1.5 A; a drops by 1.5 m

Given (f+g)(x)=10-3x and (f-g)(x)=5x-14,find f(x) and g(x).

f(x)+g(x)=10-3x
f(x)-g(x)=5x-14
f(x)=x-2
g(x)=12-4x

Find the standard equation of hyperbola satisfying the following conditions
1. The real half axis length a = 3, the imaginary half axis length b = 4
2. The focal coordinates are (0, - 6), (0,6) and (2, - 5)
3. Eccentricity e = 4 / 3, imaginary axis length 2 √ 7, focus on Y axis
4. The focal length is 10, the distance between two vertices is 6, and the vertex is on the X axis
Please tell me the specific steps, thank you very much

1 formula x ^ 2 / A ^ 2-y ^ 2 / b ^ 2 = 1 x ^ 2 / 9-y ^ 2 / 16 = 12 from the focus, we can see that C = 6 set up equations a ^ 2 + B ^ 2 = C ^ 2 = 36 4 / A ^ 2-25 / b ^ 2 = 1 solve the equation by yourself, which is the answer: 3 E = Four Thirds, imaginary axis length is 2 √ 7, C / a = Four Thirds, B = √ 7 A ^ 2 + B ^ 2 = C ^ 2