The least common multiple of three continuous natural numbers is 120
120=2*2*2*3*5
4、5、6
Among the three continuous natural numbers, the smallest one is a, and the sum of these three natural numbers is a
The other two are a + 1 and a + 2
So the sum is a + A + 1 + A + 2 = 3A + 3
Three continuous natural numbers, the smallest one is a, the other two are ()
a-2 ,a-1,a