The following four numbers all represent six digits, where n represents 0 and M represents any natural number from 1 to 9. Which one must be divisible by 3 and 5 at the same time? A.mmnmmn B.mnnmnn C.mnmnmn D.mnnnnn

The following four numbers all represent six digits, where n represents 0 and M represents any natural number from 1 to 9. Which one must be divisible by 3 and 5 at the same time? A.mmnmmn B.mnnmnn C.mnmnmn D.mnnnnn

A process of filling in the blanks? If the end is n, it can be divided by 5. If all the items add up to a multiple of three, it can be divided by 3. 3M is obviously m times of 3
c

Why can at least one of the sum, difference and product of any two natural numbers be divisible by 3?

Let any two natural numbers be x, y, and X ＞ = y. if one of X, y can be divided by 3, it is true
When x and y are not divisible by 3, then x and y are multiples of 3 (integers that can be zero) + 1 or + 2. When x + y, one is + 1 and the other is + 2, then sum can be divisible by 3. When both are + 1 or + 2, X-Y can be divisible by 3
So at least one of the sum, difference and product of any two natural numbers can be divisible by 3

The product of any natural number and 6 must be divisible by 2 and 3______ (judge right or wrong)

Because 6 is the least common multiple of 2 and 3, the product of any natural number and 6 is a multiple of 6 and can be divided by 2 and 3