A number is the continuous product of 5 2, 3 3, 2 5, 1 7. Of course, there are many divisors of this number which are two digits. Among these divisors, what is the largest?

A number is the continuous product of 5 2, 3 3, 2 5, 1 7. Of course, there are many divisors of this number which are two digits. Among these divisors, what is the largest?

97 is not a divisor of a, and 96 = 2 × 2 × 2 × 2 × 3 is a divisor of a, so the largest two digit divisor is 96

Find the natural number m, which can be divided by 2 and 25, and there are 12 divisors

Divisible by 2 and 25, it must be a multiple of 50, where
The divisors of 50 are: 1, 2, 5, 10, 25, 50 (6 in total)
The divisors of 100 are: 1, 2, 4, 5, 10, 20, 25, 50, 100 (9 in total)
The constraints of 150 are: 1, 2, 3, 5, 6, 10, 15, 25, 30, 50, 75, 150 (12 in total)
So the correct answer is 150

Find the natural number n, it can be divided by 25 and 3, and there are ten divisors

The solution of the number of factors is to decompose the prime factors and multiply the exponents of all prime factors by 1
If you have any questions about the above theorem, please ask
And N has 3 and 5 as prime factors
that
If n has 10 factors, the two exponents are 1 and 4 respectively
In addition, the exponent of 5 is at least 2, because the square of 5 gives 25,
thus
n=3×5×5×5×5=1875
[Economic Mathematics team answers for you!]