Let P: inequality x ^ 2 = 1 > A have two propositions, the solution set of P: inequality x ^ 2 = 1 > A is R; Q: 7-3a > 1 X ^ 2 = the square of X

Let P: inequality x ^ 2 = 1 > A have two propositions, the solution set of P: inequality x ^ 2 = 1 > A is R; Q: 7-3a > 1 X ^ 2 = the square of X

If your question is OK, then
From the condition in P, we can get a in P

The solution set of inequality (m ^ 2-4) x ^ 2 + (M + 2) X-1 > 0 is an empty set, and the value range of real number m is obtained

First of all, when it is not equal to x property management, that is, the coefficient in front of X is 0, then M = - 2
When we think about X again
If the solution set is empty, it means that the left horizontal is less than 0, then the opening of the image is downward and △

How to calculate 360K Π + 390 ≥ x ≥ 360 Π K + 150 when SiNx ≤ 1 / 2

It's 390 ≥ x ≥ 2 Π K + 150,
Also, radian system and angle system can't be mixed
In the function image, because the period is 2 Π, it repeats every 2K Π