(1 / 2) the skis used by skiers are 2 meters long, 10 meters wide and 10N in weight. The mass of skiers is 75kg (1 / 2) each Snowboard used by skiers is 2 meters long, 10 meters wide and 10N in weight. The mass of skiers is 75kg. When skiers stand still on the snow, their skis should be leveled

(1 / 2) the skis used by skiers are 2 meters long, 10 meters wide and 10N in weight. The mass of skiers is 75kg (1 / 2) each Snowboard used by skiers is 2 meters long, 10 meters wide and 10N in weight. The mass of skiers is 75kg. When skiers stand still on the snow, their skis should be leveled


Maybe you have the wrong number. The width is 10cm or 19.25pa
Area: 2 * 10 = 20 m2 (2 * 0.1 = 0.2 m2)
Weight 10N
Athlete f = mg = 75kg * 10N / kg = 750N (10N for G)
P=F/S=(750N+10N*2)÷(0.2㎡*2)=1925pa



When skiing, the snow layer can only bear the pressure of 2 × 10 cubic Pascal; a skier with a mass of 50 kg stands on a ski with a mass of 10 kg
(1) How much pressure does he and his skis have on the snow when they are still on a level surface?
(2) In order not to get into the snow, what is the area of the skis at least?


1. The pressure on the ground f = (M1 + m2) g = (50 + 10) * 10 = 600N (where M1 is the mass of people and M2 is the mass of skis)
2. From P = f / s, s = f / P = 600 / 2000 = 0.3m ^ 2, so the area of skis should be at least 0.3m ^ 2



If the total weight of skier and skis is 720n, when the skier stands on the horizontal snow, the pressure of skis on the snow is (2000) PA
Why is the snowboard pressure on the snow (2000) Pa, not 4000?


Standing is two feet, walking is the area of one foot



In a four stroke gasoline engine, the piston area is 5 * 10 to the power of - 3, the pressure of the high temperature air pressure generated by the combustion of the gasoline engine to the piston is 8 * 10 to the power of 5 Pa, and the work of the gasoline engine is 1.8 * 10 to the power of 6 coke after ten minutes of normal operation. What is the pressure generated by the high temperature and high pressure gas? What is the power of the gasoline engine? (2) known copper density is 40 kg, Q suction = 7.8 * 10 to the power of 6 coke, t = 550 ℃, When C copper = 0.39 * 10 coke per kilogram centigrade, find to (3) m a ratio m b = 5:3, C a ratio C B = 2:1, they give out the same amount of heat, find the increasing or decreasing temperature a ratio increasing or decreasing temperature B


(1) Pressure f = P / S = 5 power PA of 8 * 10 / 3 power m of 5 * 10; = 8 power n of 1.6 × 10
Power P = w / T = 1.8 * 10 sixth power coke / 10 × 60s = 3000W
(2) Q suction = C cu m (t-to)
To = t - Q absorption / C copper M = 550 ℃ - 7.8 * 10 cubic coke / 0.39 * 10 & # 179; J / kg ℃× 40kg = 50 ℃
(3)Q=cm△t
△t=Q/cm
Δ A / △ B = q / C a m a / Q / C B M B = C B M B / C a m a = 3 / 10



If the mass of the skier and the skier is 80 kg and the contact area of the skis is 0.4 square meters, the pressure of the skis on the snow is 10 N / kg


P=Fn/S=G/S=mg/S=80kg×10N/kg/0.4m^2=2000pa



The weight of an elephant is 6000kg, and the landing area of each foot is 600cm2. Try to calculate the pressure of the elephant on the ground when standing. (G is 10N / kg)


The pressure of elephant on the ground: F = g = mg = 6 × 103kg × 10N / kg = 6 × 104n, the area of elephant's four feet: S = 4 × 600cm2 = 2400cm2 = 0.24m2, the pressure of elephant on the ground: P = FS = 6 × 104n0.24m2 = 2.5 × 105Pa



The ballerina weighs 475n, the area of two soles is 150cm2, and the contact area between the toe and the ground is 9.5cm2 during the performance; the elephant weighs 6 × 10 quartic cow, and the area of each sole is 600cm2, (2) can the ballet dancer and the elephant walk on the frozen river? (the frozen river can bear the maximum pressure of 3.4 × 10 to the fifth power.)


1. Ballerina's pressure: P = f / s, f = g = 475n, s = 9.5cm2 = 0.00095m2, so: P = 475 / 0.00095 = 500000pa, elephant's pressure to the ground: P = f / s, f = 60000n, s = 600 × 4 = 2400cm2 = 0.24m2p = 60000 / 0.24 = 250000pa2, when walking, people think it is a foot on the ground, elephant phase



The weight of the elephant is about 6T, and the touchdown area of each foot is about 600 square centimeters. How much PA is the pressure on the ground when the elephant stands?


The pressure is equal to the pressure divided by the area under force
F=6t*9.8N/kg
S = 600 * 10-4 power
P=F/S
Do it for yourself



How to play stone scissors with feet
Such as the title


Two feet apart is cloth, two feet one before and one after is scissors, two feet together is stone
Jump up and down together and make a move
Oh, my God, how could I answer that question... --||



Xiaoming has 64 cartoon pictures and Xiaojun has 40 cartoon pictures. They play the game of stone scissors cloth. The rule of the game is that each time both sides must give the winner, Xiaojun must give the winner
How many times do you have to win over Xiao Ming to make them draw the same amount of pictures?
Need formula meaning!


12 times
(64-40)÷2=12