Choose 5 numbers from 1-6 and fill in the following formula. Find out the maximum result of the formula () * (() - ()) * (() - ())= Fill in one number for each blank

Choose 5 numbers from 1-6 and fill in the following formula. Find out the maximum result of the formula () * (() - ()) * (() - ())= Fill in one number for each blank

（ 4）*（（5 ）-（1 ））*（（6 ）-（2 ））= 64
I'm not sure if I'm going to subtract 1 from 3, so I'm not sure if I'm going to use braces

Put the eight numbers 3, 4, 5, 6, 32, 33, 34 and 35 into the following two formulas, and each number can only be used once

Sorry, that's wrong!

From the eight numbers 12345678, choose six numbers to fill in (), so that the results of each formula are the same, () - () = () - ()

8-5=7-4=6-3

A skier with a mass of M = 60kg glides freely from a slope with a height of 10m. If the resistance f is 50N and the slope angle θ is 30 ° in the process of the skier's sliding, how much work does the skier do when he slides to the bottom of the slope? What is the total work done by these forces?

The object is affected by gravity, supporting force and resistance; the work done by gravity WG = MGH = 60 × 10 × 10 = 6000J; the work done by resistance WF = - fl = - fhsin 30 ° = - 50 × 2 × 10 = - 1000j; the supporting force and the direction of motion are perpendicular to each other, so the supporting force does not work; the work done by combined external force w = WG + WF = 6000-1000 = 5000j; answer: the work done by gravity 6

A skier with mass m = 60kg glides freely from the slope with height h = 10m. Thank you
A skier with mass m = 60kg slides freely from a slope with height h = 10m. If the resistance f = 50N and the slope angle is 37 degrees, what are the work done by several forces when the skier slides to the bottom of the slope? What is the total work done by these forces?

Athletes are subject to gravity, support and friction
Gravity work WG = mg * H = 60 * 10 * 10 = 6000J
Because the direction of support force is perpendicular to the displacement direction, the work done by support force is zero
Friction work WF = - f * H / sin37 = - 50 * 10 / 0.6 = - 833.33j
The total work is WF + WG = 6000-833.33 = 5166.67j

A skier with a mass of M = 60kg glides freely from a slope with a height of 10m. If the resistance f is 50N and the slope angle θ is 30 ° in the process of the skier's sliding, how much work does the skier do when he slides to the bottom of the slope? What is the total work done by these forces?

The object is affected by gravity, supporting force and resistance; the work done by gravity WG = MGH = 60 × 10 × 10 = 6000J; the work done by resistance WF = - fl = - fhsin 30 ° = - 50 × 2 × 10 = - 1000j; the supporting force and the direction of motion are perpendicular to each other, so the supporting force does not work; the work done by combined external force w = WG + WF = 6000-1000 = 5000j; answer: the work done by gravity 6

A skier with mass m = 60kg glides freely from the slope with height h = 10m. If the resistance f = 50N, the slope angle is 0
At 30 degrees, what is the work done by the athletes in the process of sliding? What is the total work done by these forces?

W support = 0
Wgravity = MGH = 60 * 10 * 10 = 6000J
W resistance = - fl = - FH / sin30 = 2fH = 2 * 50 * 10 = - 1000j
W = 6000-1000 = 5000j