Build a rectangular pool, length 27 yuan per meter, width 35 yuan per meter, length and width integer budget 1000 yuan for the maximum area

Build a rectangular pool, length 27 yuan per meter, width 35 yuan per meter, length and width integer budget 1000 yuan for the maximum area


Oh, my God, it's all wrong
The length is x and the width is y meters
2 (27x + 35y) is less than or equal to 1000
So x is less than or equal to (500-35y) / 27
Area s = XY
Take X in, so s is less than or equal to (500-35y) * y / 27
Solve this inequality, because X and y are integers. When y = 8 meters and x = 8 meters, you can get the largest area of 64 square meters
It can also be directly taken as s = XY, when x = y, the area is the largest, and then according to 2 (27x + 35y) less than or equal to 1000, x = y is brought in
The solution is x = 8. Y = 8
The largest area is 64 square meters
The total cost is 992 yuan



The width of a rectangle is 4.8m, which is exactly 0.8 times the length. How many square meters is the area of this rectangle?


The width of a rectangle is 4.8m, which is exactly 0.8 times the length
The area of this rectangle is 4.8 x 4.8 △ 0.8
=28.8 square meters
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If the width of a rectangular land is increased by 8m and the length remains unchanged, the area will increase by 176m2; if the length is increased by 6m and the width remains unchanged, the area will increase by 96m2. What is the area of the original rectangle?


A: the area of the original rectangle is 352 square meters



How many square meters is the vegetable plot? If the vegetable plot is square, how much is the perimeter?


Length + width = 184 / 2 = 92m
Length = (1 + 0.3) * width = 1.3 width
Width: 92 / (1 + 1.3) = 40m
Length: 92-40 = 52m
Area: 52 * 40 = 2080 square meters



A rectangular vegetable field. The width is 15 meters and the area is 540 square meters. If the width is increased to 30 meters, the length will not change. What is the area of the expanded vegetable field?


Please answer as follows
The original rectangular vegetable plot area is 540 square meters, and the width is 15 meters. Then the original rectangular length = area / width = 540 / 15 = 36 meters
After expansion, the width increased to 30 meters, and the length remained unchanged to 36 meters
Expanded area = length * width = 36 * 30 = 1080 square meters



A rectangular vegetable field is 2 / 3 of the length in width and 30 meters in width. The area of this vegetable field is () square meters


1350



If the length of a rectangular vegetable field is reduced by 5 meters or the width by 3 meters, the area will be reduced by 30 square meters. What is the area of this rectangular vegetable field?


30/5=6(m)
30/3=10(m)
10*6=60(m^ 2)



The length of a rectangle is twice the width. If the length of the rectangle is reduced by 1 meter and the width is increased by 3 meters, then its area will be increased by 27 square meters. Find the length of the original rectangle


Let the original width be x meters and the length be 2x meters
2x²+27=(2x-1)(x+3)
5x=30
x=6
Then length = 12m
Width = 6M
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If the length of a rectangle is reduced by 5 meters and the width is increased by 3 meters, it will become a square and the area will be reduced by 27 square meters,
How many meters is the circumference of the original rectangle


Suppose: the length of the square is x, then the length of the original rectangle is x + 5 and the width is x-3
So, there is X & # 178; + 27 = (x + 5) * (x-3)
The solution is x = 21
Therefore, the perimeter of the original rectangle is (21 + 5) * 2 + (21 - 3) * 2 = 88 meters



If the length of a rectangle is reduced by 5 meters and the width is increased by 3 meters, it will become a square. The area will be reduced by 27 square meters. What is the perimeter of the original rectangle


x-5=y+3
xy-27=(x-5)(y+3)
y=18
x=26
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