The length of a rectangle is 3 / 5 decimeters, its perimeter is 2 decimeters, what is its width

The length of a rectangle is 3 / 5 decimeters, its perimeter is 2 decimeters, what is its width

2 △ 2-3 / 5 = 2 / 5m

When the length and width of a rectangle increase by 2 decimeters at the same time, the area will increase by 30 square decimeters. What is the perimeter of the original rectangle?

Let the length and width of a rectangle be a and B respectively
（a+2）*（b+2）=a*b+30
ab+2a+2b+4=ab+30
2a+2b=ab+30-ab-4
2（a+b)=26
a+b=13
The perimeter of rectangle is C = 2 (a + b) = 2 * 13 = 26
Therefore, the circumference of the rectangle is 26 decimeters

A rectangle is 5 / 4 meters in length and 3 / 4 in width. What's the area of the rectangle

If the width is x meters, the length is 3 / 4x meters
3/4X=5/4 X=5/3
S=5/4X=25/12.
So the rectangular area is 25 / 12 meters
Hope to help you.

The width of a rectangle is four fifths of a meter, and the length is five thirds of the width. How many square meters is the area of this rectangle?

Length = 4 / 5 × 5 / 3 = 4 / 3M
Area = 4 / 5 × 4 / 3 = 16 / 15 square meters

The length of the rectangle is 85 meters, which is four times the width. What is the area of the rectangle?

A: the area of a rectangle is 1625 square meters

A rectangle is four times the width and 120 meters in circumference. How many square meters is the area of this rectangle?

A: the area of this rectangle is 576 square meters

When x = - 5 / 3, find the value of (1-x) &# 178; - 4 (1-x & # 178;) + 4 (1 + x) &# 178;)

The original formula = [(1-x) - 2 (1 + x)] & #178;
=(-3x-1)²
=(5-1)²
=16

Given that x + 1 / x = 3, find the value of the algebraic formula x + 1 / X & # - 5-1 / X-X

∵x+1/x=3
∴(x+1/x)²-5-1/x-x
=3²-5-(1/x+x)
=9-5-3
=1

When a + B = 6, find the square of (A's Square - B's Square) - 8 (A's square + B's Square)

（a^2-b^2）^2-8（a^2+b^2）
=(a+b)^2(a-b)^2-8(a+b)^2+16ab
=36(a-b)^2-288+16ab
=36(a+b)^2-144ab-288+16ab
=1008-128ab

The square of Y + 2Y + 7 = 8, y =?

The original equation is: Y & # 178; + 2y-1 = 0
(y-√ 2 +1)(y+√ 2+1)=0
y1=√ 2-1,y2=-√ 2-1.