If the sum of the formulas of two nonnegative numbers is 0 (or the two formulas are opposite to each other), then the two formulas are equal to - ---, that is, the nonnegative conditional formula

If the sum of the formulas of two nonnegative numbers is 0 (or the two formulas are opposite to each other), then the two formulas are equal to - ---, that is, the nonnegative conditional formula

Because "non negative number" = 0 and positive number, and positive number must add negative number to be able to = 0, and negative number does not meet the condition of "non negative number", so these two formulas can only be = 0

Three methods of finding 2 34 5 6 7 8 9 = 10 plus sign

Sum of 2 3 4 5 6 7 8 9 = (2 + 9) * 8 / 2 = 44
The result was 10
Plus plus minus sign, in fact, is divided into two groups, the difference is 10, you can find the subtracted
（44-10）/2=17
17 = 8 + 9 = 8 + 4 + 5 = 3 + 5 + 9 = 4 + 6 + 7, etc
Just add a minus sign to the front, and the rest is exactly
as
2+3+4+5+6+7-8-9=10
2+3-4+5-6-7+8+9=10
2+3-4-5+6+7-8+9=10

5 10 4 10 6 is rewritten as multiplication and 7 10 8 10 9

5×3＝15 8×3＝24

If for any x ＞ 0, x-2x + 4 ≤ λ is constant, then the value range of λ is constant

∵ x ＞ 0, (X & # 178; - 2x + 4) / X ≤ λ
∴x²-(2+λ)x+4≤0
∴(2+λ)x≥x²+4
∴2+λ≥(x²+4)/x＝x+4/x≥2√x·2/√x=4
∴λ≥2

It is known that f (x) = 1 - (the x power of 2 / 2 + 1). TF (x) > = 2x square - 2 is constant. X belongs to (0,1]. The range of T is obtained

Because f (x) is always greater than 0 on (0,1), we separate the variables into t > = (2x ^ 2-2) (2 ^ x + 1) / (2 ^ x-1)
Therefore, only t is greater than the maximum value of the function on the right side, and it is easy to know that the function on the right side is an increasing function at (0,1), so t > = 0

When 0 ≤ m ≤ 1, (2x-1)

m(x²+1)

Given (X-2) 2 + | 2x-3y-a | = 0, y is a positive number, then the value range of a is______ ．

According to the meaning: X − 2 = 02x − 3Y − a = 0, the solution: x = 2Y = 4 − A3, according to the meaning: 4 − A3 > 0, the solution: a < 4

Given (X-2) 2 + | 2x-3y-a | = 0, y is a positive number, then the value range of a is______ ．

According to the meaning: X − 2 = 02x − 3Y − a = 0, the solution: x = 2Y = 4 − A3, according to the meaning: 4 − A3 > 0, the solution: a < 4

Given (X-2) 2 + | 2x-3y-a | = 0, y is a positive number, then the value range of a is______ ．

According to the meaning: X − 2 = 02x − 3Y − a = 0, the solution: x = 2Y = 4 − A3, according to the meaning: 4 − A3 > 0, the solution: a < 4

The square of (x-3) + | 2x-3y-a | = 0, y is a positive number, and the value range of A

Square of (x-3) + 2x-3y-a = 0
The square of (x-3) = 0, 2x-3y-a = 0
x-3=0,2x-3y-a=0
X=3
Substituting 2x-3y-a = 0
2*3-3y-a=0
3y=6-a
y=（6-a）/3
If y is a positive number, then
y>0
（6-a）/3>0
6-a>0
a