How many catties does a round iron plate with a circumference of 5.4 meters, a diameter of 1.6 meters and a thickness of 25 centimeters have

How many catties does a round iron plate with a circumference of 5.4 meters, a diameter of 1.6 meters and a thickness of 25 centimeters have

The volume product of circular iron plate is: (radius: 1.6 / 2 = 0.8 cm), 0.8 * 0.8 * 3.14 * 25 = 50.24 cubic cm
50.24 * specific gravity = the weight of this round iron plate (the specific gravity can be found in the hardware manual)

Mass of 1.5m wide, 2.5m long and 3mm thick Metro slab

Density of iron plate? (the default is p = 7.8759 × 10 & # 179; kg / M & # 179;)
The volume of iron plate is v = 1.5 * 2.5 * 0.003 = 0.1125m and 179;
The mass of iron plate M = V * P = 0.1125 * 7.8759 × 10 & # 179; = 886.03875kg

A piece of iron plate is 2m long, 1.5m wide and 3cm thick. How much is it?

Volume 2 * 1.5 * 0.03 = 0.09 mass 0.09 * 7.19kg = 0.6471

How much does the 2 cm thick 90 wide 160 long iron plate weigh
90cm wide and 160cm long

The volume of iron
V=2×90×160
=28800cm3
The density of iron is 7.8g/cm3
therefore
m=pV
=7.8×28800
=224640g
=224.64kg
It's about 450 Jin

An iron plate, 30 cm long, 30 cm wide and 1.2 cm thick, what's its weight

About 8532 G

How much is an iron plate 1 meter long, 0.4 meters wide and 0.16 meters thick?

1×0.4×0.16×7.8
=0.064×7.8
=0.4992 (T)
=499.2 (kg)

For weight, an iron plate is 6 meters long, 1.5 meters wide and 5 mm thick

The density of iron is 7.9g/cm3, the volume of iron plate is 600 * 150 * 0.5 = 45000cm3, the mass is 355500g = 355.5kg = 711 kg, and the weight is 9.8 * 355.5 = 3483.9n

How much is 600 times 720 for 16 Li iron plate?

600 times 720 = 432000

3mm iron coil a diameter of 800mm iron barrel, ask how long iron plate?
Please write the calculation process and related formula. Thank you!

800mm*3.14=2512mm
（800-6）*3.14=2493.16mm
(2512+2493.16)/2=2502.58mm
The formula is: diameter * 3.14 = perimeter
Results: (outer perimeter + inner perimeter) / 2
Namely: 2502.16mm

As shown in the figure is a quadrilateral iron plate, angle B is equal to angle D is equal to 90 degrees, ab = ad = 9, BC = CD = 12
There are two ways to cut a rectangular iron plate: (1) take AB side as the rectangular side;
(2) A set of opposite sides of the rectangle are parallel to AC
If the area of the cut rectangle is as large as possible, which method should be used?

S = 1 / 2 * x * y = 5x * y = 10 ------ (1) from the question, we can get: the area of trapezoid is s = 1 / 2 * (AB + CD) * ad = 1 / 2 * (6 + 4) * 2 = 10. When we cut out the rectangle aefg, the area of trapezoid is s = s rectangle + s trapezoid '+ s triangle = 5 + 1 / 2 * (DC + y) * (ad-x) + 1 / 2 * (ab-y) * x = 10 (...)