If the length of a rectangle remains unchanged and its width increases by 4 meters, it will become a square and its area increases by 36 square meters. What is the area of the original rectangle?

If the length of a rectangle remains unchanged and its width increases by 4 meters, it will become a square and its area increases by 36 square meters. What is the area of the original rectangle?

Solution:
If the width of the rectangle is increased by 4 meters, the area will be increased by 36 square meters, and the length of the rectangle is 36 △ 4 = 9 meters
If the width of a rectangle increases by 4 meters, it will turn into a square. Then the length of the rectangle is 4 meters longer than the width, and the width of the rectangle is 9-4 = 5 meters
Rectangular area = length × width = 9 × 5 = 45 square meters

A rectangle. Length unchanged, width more than 4 meters, area more than 36 square meters, then it becomes a square, find the original rectangle?

Suppose the length of the original rectangle is y and the width is x, then x + 4 = y has an area of 36 square meters more, 4 times y = 36, y = 9, then x = 9-4, x = 5, and the original rectangle is 5 times 9 = 45

There is a rectangle. If the length is reduced by four meters and the width is reduced by two meters, the area will be reduced by 44 square meters, and the remaining part is just a square
The perimeter of a square

There must be something wrong with the title
The length and width have been reduced by a few meters, at least a few square meters
If the title is changed as follows:
If the length of a rectangle is reduced by 4 decimeters and the width by 2 decimeters, the area will be reduced by 44 square decimeters, and the rest will be a square
Let the side length of a square be x decimeters
(X+4)(X+2)=X²+44
X²+6X+8=X²+44
X=36/6
=6
Perimeter = 4 * 6 = 24 decimeters