If the image of the linear function y = KX + B passes through the point (2,3), y increases by three units every time x increases by one unit, then the analytic formula is

If the image of the linear function y = KX + B passes through the point (2,3), y increases by three units every time x increases by one unit, then the analytic formula is

From the meaning of the problem, we know that the function y = KX + B passes through (2,3) (3,6)
Substituting (2., 3) (3,6) into the first-order function y = KX + B, we get
3=2k+b
6=3k+b
The solution is k = 3
b=-3
So the analytic expression of a function is y = 3x-3

The first-order function y = KX + B, when 1 is less than or equal to X and less than or equal to 3, 1 is less than or equal to y and less than or equal to 3, find the value of K and B

When k ＞ 0, (1-B) / K ≤ x ≤ (3-B) / K  1-B) / k = 1 (3-B) / k = 3, k = 1, B = 0, y = B ∫ B ∈ R ∫ does not conform to the meaning. When k ＜ 0, (1-B) / K ≥ x ≥ (3-B) / K 1-B) / k = 3 (3-B) / k = 1, k = - 1, B = 4