Under the same conditions, the volume of 1 mol matter in different states is different, and it is usually 1 1. Under the same conditions, the volume of 1 mol matter in different states is different, which is usually 1; 2. The volume of 1 mol solid or liquid under the same conditions; 3. Under the same conditions, the volume of 1 mol gas is approximate

Under the same conditions, the volume of 1 mol matter in different states is different, and it is usually 1 1. Under the same conditions, the volume of 1 mol matter in different states is different, which is usually 1; 2. The volume of 1 mol solid or liquid under the same conditions; 3. Under the same conditions, the volume of 1 mol gas is approximate

1. Under the same conditions, the volume of 1 mol matter in different states is different
solid

How to calculate the volume of 1mol solid or liquid substance
Can the volume of gaseous matter be calculated by V = NVM under the condition of knowing the state, and the volume of solid and liquid can also be calculated? If so, what factors affect its volume? Temperature and pressure?

The volume of solids and liquids can only be determined by volume = mass / density
The volume of a solid is almost independent of pressure and temperature
The volume of liquid is almost not affected by pressure, but it is affected by temperature
So both can only be calculated by volume = mass / density

Volume of 1mol substance under standard condition
Under standard conditions, the largest volume of the following substances is? A.fe b.o2 c.h2o d.h2so4

This problem does not need to be calculated. Under the standard condition (0 ℃, 101kpa), a is a solid, CD is a liquid (C may be a solid or a mixture of solid and liquid), and B is the same number of molecules of gas. The volume of gas is much larger than that of solid and liquid (because the volume of solid and liquid is determined by the molecular size, The volume of gas is determined by the distance between molecules; the distance between molecules is about 10 times the radius of molecules

Please add a condition to the following question before you answer it___ 37 of the total was used the next day. How many kilograms were used the next day?

It can be added that 27.14 △ 27 × 37 = 49 × 37 = 21 (kg) of the total was used in the first day. A: 21 kg was used in the second day

A barrel of oil uses 45, and then adds 15 kg. At this time, the gasoline in the barrel is exactly 12 times of that in the whole barrel. How many kg of gasoline is this barrel?

15 △ 12 - (1-45)] = 15 △ 12-15] = 15 △ 310 = 50 (kg) a: this barrel of gasoline is originally 50 kg

5 / 8 of a barrel of gasoline is used up, and there are 15 kilograms left. How many kilograms of this barrel of gasoline are there?

It used to be 15 (1-5 / 8) = 40 kg

A barrel of gasoline used 25 kg, used 10 kg, how many kg of this barrel of gasoline?

A: this barrel of gasoline is 25 kg

A barrel of gasoline, used 15 kg, is exactly 1 / 3 of the original. How many kg of the original barrel of gasoline, how many kg left?

1. After 15 kg, the remaining one-third, then 15 kg is two-thirds
So there's 15 / two-thirds of this barrel of gas = 22.5
2. 15 kg is one third of the original 45 kg, 30 kg left

For a barrel of gasoline, the mass of the barrel is 8% of that of the gasoline. After 48 kg of gasoline is poured out, the mass of the oil is half of that of the barrel. How many kg of the barrel and the original gasoline are each?

Suppose the original oil is XKG, then the barrel weight is 8% kg, then we can get: x-48 = 50% × 8% xx-48 = 4% x96% x = 48 & nbsp; & nbsp; X = 50.50 × 8% = 4 (kg) answer: the barrel weight is 4kg, and the original gasoline weight is 50kg

It is known that the efficiency of diesel engine is 40% and the calorific value of diesel is 4x10 to the seventh power J / kg. Using this device, a 3200n building material can be lifted by 5m for 4S
The consumption of diesel oil is 4G
(1) How much heat does 4G diesel give out after complete combustion? What is the output power of diesel engine?
(2) What is the useful work to improve this building material? What is the mechanical efficiency of the whole device?

(1) Heat released from complete combustion of 4G diesel: q = MQ = 0.004kg × 4000 0000j / kg = 160000j
External work of diesel engine: wtotal = 40% q = 40% × 160000j = 64000j
Output power of diesel engine: P = w △ t = 640000j △ 4S = 16000w
(2) The useful work of improving this building material: W useful = GH = 3200n × 5m = 16000j
Mechanical efficiency of the whole device: η = w useful △ w total = 16000j △ 64000j = 25%
Which of the above is not clear can be specifically pointed out and asked