There are 100 tons of clean water tanks in the waterworks. Three water pipes of the same size are used to deliver water at the same time. After t hours, the water is discharged, Each pipe is known to drain x tons per hour 1. Write the functional relationship between T and X 3. When t = 10, calculate the value of X

There are 100 tons of clean water tanks in the waterworks. Three water pipes of the same size are used to deliver water at the same time. After t hours, the water is discharged, Each pipe is known to drain x tons per hour 1. Write the functional relationship between T and X 3. When t = 10, calculate the value of X

1. Write the functional relationship between T and X
T=100/(3X)
3. When t = 10, calculate the value of X
From t = 100 / (3x)
X = 100 / (3T) = 100 / (3 * 10) = 3.33333 H (3 and 1 / 3 h)

There is 450 tons of water in the reservoir of a waterworks. The waterworks can inject 80 tons of water into the reservoir every hour. At the same time, the reservoir also supplies water to the residents of the community
There is 450 tons of water in the reservoir of a waterworks. The waterworks can inject 80 tons of water into the reservoir every hour. At the same time, the reservoir also supplies water to the residents of the community. The total amount of water supply in t hours is 80 tons. Now we start to inject water into the reservoir and supply water to the residents of the community at the same time. Then (1) how many hours will the water in the reservoir be the least, (2) if the stock in the reservoir is less than 150 tons, there will be a shortage of water supply, How many hours a day is the water supply tight

Let's set the water volume of the reservoir as X tons, x = 80t-80 √ 20t, cough, and then calculate by ourselves. It's not easy to calculate if I have paper and pen. There's a formula, find the root, and then find the lowest point. The second step is X

The water storage tank of a waterworks has 400 tons of water. The waterworks can inject 60 tons of water into the reservoir every hour. At the same time, the reservoir continuously supplies water to residential quarters. The total amount of water supply within t hour is 1206 tons (0 ≤ t ≤ 24). From the beginning of water supply to the hour, the water storage in the reservoir is the least? What is the minimum quantity of water?

Let the volume of water in the reservoir be y tons after t hours, then y = 400 + 60t − 1206t (0 ≤ t ≤ 24), let 6T = x, that is, X2 = 6T, and X ∈ [0,12], that is, y = 400 + 10x2-120x = 10 (X-6) 2 + 40, ∧ when x = 6 ∈ [0,12], that is, t = 6, Ymin = 40, a: from the beginning of water supply to the sixth hour, the volume of water in the reservoir is the least, only 40 tons