If the volume of a hollow shot is 3054g, we can judge whether it is a large shot by calculating the volume of the hollow shot The density of aluminum is 2.7 × 10 cubic kg / M cubic

If the volume of a hollow shot is 3054g, we can judge whether it is a large shot by calculating the volume of the hollow shot The density of aluminum is 2.7 × 10 cubic kg / M cubic

If the volume is calculated according to M = PV, then v = m / P = 54G / 2.7g/cm ^ 3 = 20 ^ cm3
But the actual volume is 30cm ^ 3, so it can be judged that the ball is hollow
The volume of the hollow part is 30cm ^ 3-20cm ^ 3 = 10cm ^ 3
The question "if it's hollow, what's the volume?" seems a little wrong. It should be "if it's hollow, what's the volume of the hollow part",

A hollow aluminum ball weighs 125 N and has a volume of 15 cubic decimeters. If it is put into water, will it float or sink? What is the buoyancy when it is still?

Because g ball = m ball g (g = 10N / kg)
So m-ball = 12.5kg
V-ball = 15dm & # 179;
So p-ball = m-ball / v-ball
83 kg / DM and 179;
P-ball

What is the buoyancy of a 4.5n hollow metal ball with a volume of 0.5 cubic decimeter after it is put into the water gently

pgV=5N>4.5N
So the ball floats
F = g = 4.5n