A hollow shot has a mass of 540g and a volume of 600cm. When it is put into enough water to stand still, how much buoyancy does it bear? (g = 10N / kg) . speed point O (∩)__ ∩)O

A hollow shot has a mass of 540g and a volume of 600cm. When it is put into enough water to stand still, how much buoyancy does it bear? (g = 10N / kg) . speed point O (∩)__ ∩)O

This question in addition to test knowledge, but also test flexible use of knowledge
When looking at the questions, I immediately feel the following points: 1. Hollow - will it be lighter than water; 2. The mass is 540g, and the volume is 600cm - it is lighter than water (I have learned that the density of water is 1g per cubic centimeter!) 3. It is floating, and the buoyancy is equal to the weight (0.540 * 10)
How about that?

A 2n tomato floats on the water. (take g = 10N / kg) find: (1) the buoyancy of the tomato; (2) the volume of boiling water discharged by the tomato

Because of the floating of tomatoes, f-floating = g = 2n, according to the buoyancy formula: V row = f-floating ρ water, g = 2n1.0 × 103kg / m3 × 10N / kg = 2 × 10-4m3. Answer: (1) the buoyancy of tomatoes is 2n; (2) the volume of boiled water discharged by tomatoes is 2 × 10-4m3

Second grade physics buoyancy class after the question "if the iron block into kerosene, compared with the aluminum block into the water, which of them is more buoyant? Why?"
The second grade physics buoyancy class after the question "the same volume of iron and aluminum block into the water are submerged. If the iron block into kerosene, compared with the aluminum block into the water, which of them is more buoyant? Why? The answer and sink to the bottom of this condition has nothing to do with?

This is a problem with insufficient conditions
To solve this kind of problem, we should compare the volume of iron and aluminum immersed in kerosene and water
Solution: F floating = ρ liquid GV row, and then compare after calculation