The speed of passenger cars on expressways is usually several kilometers per hour
The carts are generally 90-110 km long
The speed of car a on the highway is 100 km / h, and that of car B is 120 km / h. at this moment, car a is 80 km in front of car B, and car a will continue to drive forward after refueling and parking for 10 minutes. How long will it take car B to catch up with car a at least from 80 km away?
10 minutes = 1 / 6 hour
10 minutes B car (1 / 6) × 120 = 20 (km)
Time required for B to catch up with a: (80-20) / (120-100) + 10 minutes
=3 (hours) 10 minutes
A car from a to B, the first 1 / 3 of the road for the ordinary highway, the rest of the road for the highway
A car from a to B, the first 1 / 3 of the road for ordinary highway, the rest of the road for highway. It is known that the speed of a car is 60km / h on an ordinary highway and 100km / h on an expressway. It takes 2.2 hours for a car to travel from a to B. how many kilometers are there from a to B
1 set the distance between a and B as m km, m multiplied by 1 / 3 = 1 / 3M is the distance of ordinary highway, m multiplied by (1-1 / 3) = 2 / 3M is the distance of expressway, 2 time multiplied by speed = distance, in other words, time = distance / speed, driving time of ordinary highway = 1 / 3M divided by 60km / h = m / 180, high speed = 2 / 3M divided by 100km /