The big rectangle can be divided into three small rectangles of the same size. The perimeter of the big rectangle is 8 decimeters. What is the area of the big rectangle?

A large rectangle can be divided into three small rectangles of the same size: let the length of the original rectangle be x, then the width be (8 / 2 - x) = 4-x, and then it can be divided into three small rectangles of the same size: (x / 3) / (4-x) = (4-x) / XX ^ 2 / 3 = (4-x)

The big rectangle can be divided into three small rectangles of the same size. The perimeter of the big rectangle is 8 decimeters, and the area of the big rectangle
I want the process, my primary school, to write some students can understand the process, pictures can not be put on (left one vertical, right two horizontal)

If the width of a small rectangle is x decimeters, the width of a large rectangle is 2x decimeters and the length is 3x decimeters
2（2x+3x)=8
The solution is x = 0.8
The length of large rectangle is 3x = 3 * 0.8 = 2.4 (decimeter)
The width of large rectangle is 2x = 2 * 0.8 = 1.6 (decimeter)
The area of large rectangle is 2.4 * 1.6 = 3.84 (square decimeter)

A large rectangle can be divided into three small rectangles of the same size. The perimeter of a large rectangle is 8 decimeters

64 / 3 root sign 3

Cut the circle into an approximate rectangle, the perimeter of the rectangle is compared with the original (), the area is compared with the original ()
A. Bigger B. smaller C. no change
Just answer the letters in the order of the questions

If it is splicing after cutting, then the area remains unchanged compared with the original, and the perimeter becomes longer compared with the original

If LG2 = A and Lg3 = B are known, then lg12lg15 = a___ ．

Lg12lg15 = LG (3 × 4) LG (3 × 5) = Lg3 + lg4lg3 + lg5 = Lg3 + 2lg2lg3 + lg102 = Lg3 + 2lg2lg3 + 1-lg2, ∵ LG2 = a, Lg3 = B, ∵ lg12lg15 = 2A + bb-a + 1, so the answer is: 2A + bb-a + 1

If LG2 = A and Lg3 = B are known, then lg12lg15 = a___ ．

Lg12lg15 = LG (3 × 4) LG (3 × 5) = Lg3 + lg4lg3 + lg5 = Lg3 + 2lg2lg3 + lg102 = Lg3 + 2lg2lg3 + 1-lg2, ∵ LG2 = a, Lg3 = B, ∵ lg12lg15 = 2A + bb-a + 1, so the answer is: 2A + bb-a + 1

If LG2 = a, Lg3 = B, what is LG12 / LG15

LG12 = LG4 + Lg3 = 2lg2 + Lg3 = 2A + B LG15 = lg30-lg2 = Lg3 + lg10-lg2 = B + 1-A original formula = (2a + b) / (B + 1-A)

If LG2 = a, Lg3 = B, then LG15 =?

lg5=1g10-lg2=1-a
lg15=lg3+lg5=b+1-a

Log2 = LG2? Are these two equal
The computer results are the same,

It's log10 2 = LG2

(lg5) ^ 2 + lg2lg50 + 2 ^ ((1 + 1 / 2 (log2 (5)))) = 2 + 2 √ 5? = (1-lg2) ^ 2 + lg2lg10 + 1-lg2 + 2 √ 5 note
Note lg5 = 1-lg2

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The big rectangle can be divided into three small rectangles of the same size. The perimeter of the big rectangle is 8 decimeters. What is the area of the big rectangle?