The answer is coming soon, (x-1) 2 + 2x (x-1) = 0 2x2-4x-5 = 0 - 3x2-4x + 4 = 0 2 (y + 4) 2 + y (y + 4) = 0 1:（x-1）2+2x（x-1）=0 2:2x2-4x-5=0 3:-3x2-4x+4=0 4:2(y+4)2+y(y+4)=0

The answer is coming soon, (x-1) 2 + 2x (x-1) = 0 2x2-4x-5 = 0 - 3x2-4x + 4 = 0 2 (y + 4) 2 + y (y + 4) = 0 1:（x-1）2+2x（x-1）=0 2:2x2-4x-5=0 3:-3x2-4x+4=0 4:2(y+4)2+y(y+4)=0

1. (x-1) ^ 2 + 2x (x-1) = 0x ^ 2-2x + 1 + 2x ^ 2-2x = 03x ^ 2-4x + 1 = 0 (3x-1) (x-1) = 0x1 = 1 / 3 x2 = 12.2x ^ 2-4x-5 = 0 x ^ 2-2x + 1 = 3.5x-1 = soil √ 3.5x1 = 1 + √ 3.5x2 = 1 - √ 3.53. - 3x ^ 2-4x + 4 = 03x ^ 2 + 4x-4 = 0 (3x-2) (x + 2) = 0x1 = 2 / 3 x2 = - 2 4.2 (y + 4) ^ 2 + y (y +

Solve the following inequality (1) 3x2-2x + 1

x∈∅
X ∈ (- 2 / radical 3, + 2 / radical 3)
x∈R
x=0

First dissolve, then evaluate: 2x2-4x / x + 2 times x2 + 2x / x2-4x + 4 + 4x / 2-x, where x = 1 / 2
2x2-4x / x + 2 times x2 + 2x / x2-4x + 4 + 4x / 2-x, where x = 1 / 2
All brothers and sisters basic training 53 questions 3

The original formula = (2x (X-2) / x + 2) * x (x + 2) / (X-2) 2 + 4x / 2-x
=2x2/（x-2）-4x/x-2
=2x（x-2）/（x-2）
=2x
=1