1. When x = 2, the value of ax ^ 5 + BX ^ 3 + CX-7 is - 10. When x = - 2, find the value of the algebraic formula 2. Calculate 100 ^ 2-99 ^ 2 + 98 ^ 2-97 ^ 2 + 96 ^ 2-95 ^ 2 +. + 2 ^ 2-1 ^ 2 3. The polynomial a ^ 2 + (A-3) x ^ 2-9x ^ 3-9x ^ 3 + X + 1 is about the quadratic trinomial of X, to find the value of the algebraic formula (A-1) (a ^ 2 + A + 1)

1. When x = 2, the value of ax ^ 5 + BX ^ 3 + CX-7 is - 10. When x = - 2, find the value of the algebraic formula 2. Calculate 100 ^ 2-99 ^ 2 + 98 ^ 2-97 ^ 2 + 96 ^ 2-95 ^ 2 +. + 2 ^ 2-1 ^ 2 3. The polynomial a ^ 2 + (A-3) x ^ 2-9x ^ 3-9x ^ 3 + X + 1 is about the quadratic trinomial of X, to find the value of the algebraic formula (A-1) (a ^ 2 + A + 1)

1. Take ax ^ 5 + BX ^ 3 + CX-7 as two parts, ax ^ 5 + BX ^ 3 + CX and - 7 as variable and invariant parts
When x = 2, ax ^ 5 + BX ^ 3 + CX-7 = - 10, then ax ^ 5 + BX ^ 3 + CX = - 3, x = 2
So when x = - 2, ax ^ 5 + BX ^ 3 + CX = 3
ax^5+bx^3+cx-7=3-7=-4
2, the original formula = (100 + 99) (100-99) + (98 + 97) (98-97) + ·· + (2 + 1) (2-1) = 199 + 195 + ·· + 3 = 0.5 (199 + 3) * 49 = 4949 (98 items, 49 pairs and 199 + 3 = 202)
3. The third question you wrote is a bit confusing and problematic
Hello, yes, yes. Send it back

As shown in the figure, an isosceles trapezoid flowerbed is designed. The upper bottom of the flowerbed is 100m long, the lower bottom is 180m long, and the distance between the upper and lower bottom is 80m. There is a transverse corridor outside the middle line of the two waist, and there are two longitudinal corridors between the upper and lower bottom. The width of each corridor is equal, and the area of the corridor is one sixth of the trapezoid area. What is the width of the corridor (accurate to 0.01M)? (friendly tip: the median line of the middle corridor is the median line of the isosceles trapezoid)

Let the width of the corridor be XM. According to the meaning of the title, we can get 100 + 1802x + 2x × 80-2x2 = 16 × 100 + 1802 × 80. After sorting out, we can get 3x2-450x + 2800 = 0, ｜ X1 = 225 + 516893 ＞ 80 (rounding off), X2 = 225 − 516893 ≈ 6.50 A: the width of the corridor is about 6.50m

Decompose x ^ + X-2 + √ 2 into factors in the range of real numbers to get the correct rate
And···
When a

Let X & sup2; + X-2 + √ 2 = 0
The solution is: X1 = - √ 2, X2 = √ 2-1
∴x²+x-2+√2=(x+√2)(x-√2+1)
∵a

A natural number, the sum of the digits in 3 is 24. The minimum sum of the digits in 9 is 24______ The biggest is______ ．

From the right, the even position is 0, and the odd position is 13: 1, 01, 01 01, 01 (24 ones) 9 base: 1, 1, 1 1 (24 1) digits and minimum: a case of 24 digits and maximum, from the right

For a natural number, the sum of digits in the ternary system is 24. What is the minimum and maximum sum of digits in the ninth system?

If the sum of digits in ternary system is 24, the largest number in ternary system is expressed as
111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111,
The smallest number is expressed as
222 (12 2)
So the maximum sum of digits in the ninth system is: (a group of two) (11 in the third system is 4 in the ninth system)
4444 (12 4)
The smallest is: (22 in ternary is 8 in 9)
eight hundred and eighty-eight thousand eight hundred and eighty-eight

Express some natural numbers in decimal system, which is exactly 16 times of the sum of its digits?

Let n be the number of digits of this number, (1) when n = 1, let a bit be a, then 16A = a, the solution is a = 0; (2) when n = 2, let a bit and ten bits be a and B respectively, then 16 (a + b) = 10B + A, that is 6B + 15A = 0, ∵ A is an integer from 0 to 9, B is an integer from 1 to 9, ∵ left is greater than 0, not true, rounding off; (3

C + + conversion from 10 to 16
// Note:Your choice is C++ IDE
#include
using namespace std;
int main()
{
int i,j,n=0;
char k[20];
char s[17]={'0','1','2','3','4','5','6','7','8','9','A','B','C','D','E','F'};
couti;
while(i!=0)
{
j=i%16;
k[n]=s[j+1];
j=j/16;
n++;
}
cout

Modify as follows: ා include using namespace STD; int main() {int i, J, n = 0; char K [20]; char s [17] = {0 ','1','2 ','3','4 ','5','6 ','7','8 ','9','a ','b','c ','d','e ','f'}; couti; while (I! = 0) {J = I% 16; K [n] = s [J]

X-2y-3z = 0 2x + y-2z = 0 find the value of X: Y: Z

x-2y-3z=0 ①
2x+y-2z=0 ==> 4x+2y-4z=0 ②
①+2*②==>5x-7z=0 ==>x:z=7:5
x-2y-3z=0 ==> 2x-4y-6z=0 ③
2x+y-2z=0 ④
④-2*③==>5y+4z=0 ==>y:z=-4:5
x:z=7:5
y:z=-4:5
==>x:y:z=7:(-4):5

x+2y+z=0 x-y+2z=2 2x-y+3z=-1

X + 2Y + Z = 0, X-Y + 2Z = 2 2x-y + 3Z = - 1 x + 2Y + Z = 0, ① X-Y + 2Z = 2, ② 2x-y + 3Z = - 1, ③ ① - ② 3y-z = - 2, ④ 2 * ① - ③ 5y-z = 1, ⑤ 5 * ④ - 3 * ⑤ - 2Z = - 13, z = 13 / 2 substituting Z to ④, y = 3 / 2 substituting y and Z to ①, x = - 19 / 2, so x = - 19 / 2

If a and B are reciprocal, and seven out of a = B out of X, then what is 2x

7/a=b/x
Because: A and B are reciprocal
So: a = 1 / b
7b=b/x
x=1/7
So: 2x = 2 / 7