Given x2 + 4x + y2-10y + 29 = 0, find the value of X + 2Y / x2-2y2

Given x2 + 4x + y2-10y + 29 = 0, find the value of X + 2Y / x2-2y2


(x + 2) + (Y-5) = 0
So x = - 2, y = 5
Just put in the value



How to make y = ½ X & #178; - 6x + 21 = ½ (X-6) x & #178; + 3


y=½x² - 6x ＋ 21
=1/2(x²-12x)+21
=1/2(x-6)²-6²*1/2+21
=1/2(x-6)²+3



Solutions to X & # 178; - Y & # 178; + X + y and X & # 179; - XY & # 178; + X + y


x²-y²+x+y
=（x+y）（x-y）+x+y
=(x+y)(x-y+1)
x³-xy²+x+y
=x(x²-y²)+x+y
=x(x+y)(x-y)+x+y
=(x+y)(x²-xy+1)
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